![x= \sqrt[8]{y} \\ y = z^{16} ](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B8%5D%7By%7D%0A%5C%5C%20y%20%3D%20z%5E%7B16%7D%0A%0A%20)
Plug "y" into the first equation.
![x = \sqrt[8]{z^{16}} = (z^{16})^{1/8} = z^{16/8} = z^2](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B8%5D%7Bz%5E%7B16%7D%7D%20%3D%20%28z%5E%7B16%7D%29%5E%7B1%2F8%7D%20%3D%20z%5E%7B16%2F8%7D%20%3D%20z%5E2)
The answer is 0.154 m
Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒ V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³
Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625 / 0.405
d = 0.154 m
The answer is b becuase my sister had that homework
Answer:
I don't know
Step-by-step explanation:
because I don't see the pattern
