Answer:
Step-by-step explanation:
<u>Use points on the graph:</u>
<u>Find the slope:</u>
<u>The y-intercept is known b = 7, so the equation is:</u>

Keep in mind: The entire line segment (VX) is equal to 14.

Let's see how the line segment looks like first.
Line segment VX is 14 units long.
14
______________
V X
W is on the line segment somewhere, and VW is equal to 3.
3 ?
______________
V W X

We have to solve for the <em>?.</em> Let's put ? as x. So now we are solving for x.
We have to set up our equation like this:
x + 3 = 14
Since our unknown value plus 3 is equal to 14, we have to subtract 3 from 14 to get our answer.
14 - 3 = 11
3 11
______________
V W X

Answer:
y-intercept: 10
concavity: function opens up
min/max: min
Step-by-step explanation:
1.) The definition of a y-intercept is what the resulting value of a function is when x is equal to 0.
Therefore, if the function's equation is given, to find y-intercept simply plug in 0 for the x-values:

y intercept ( f(0) )= 10
2.) In order to find concavity (whether a function opens up or down) of a quadratic function, you can simply find the sign associated with the x^2 value. Since 2x^2 is positive, the concavity is positive. This is basically possible, since it is identifying any reflections affecting the y-values / horizontal reflections.
3.) In order to find whether a quadratic function has a maximum or minimum, you can use the concavity of the function. The idea is that if the function opens downwards, the vertex would be at the very top, resulting in a maximum. If a function was open upwards, the vertex would be at the very bottom, meaning there is a minimum. Like the concavity, if the value associated with x^2 is positive, there is a minimum. If it is negative, there is a maximum. Since 2x^2 is positive, the function has a minimum.