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2 years ago

Find the hypotenuse (c) of the right triangle.

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

4 0

<h2><u>Solution</u>:-</h2>

Hypotenuse (x) of the right triangle = $\sqrt{7² \: + \: 11²}$

Hypotenuse (x) of the right triangle = $\sqrt{49 \: + \: 121}$

Hypotenuse (x) of the right triangle = $\sqrt{170}$

Hypotenuse (x) of the right triangle = 13

The hypotenuse (x) of the right triangle is <u>1</u><u>3</u><u> </u><u>m</u>.

<h3>Hence, option (D) <u>1</u><u>3</u><u> </u><u>m</u> is correct. [Answer]</h3>

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3 years ago

Which equation represents the circle described? (in picture)

Sedaia [141]

You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.

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Complete the square:

$x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2$

And we have:

$(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
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So the answer is C (the same left side of equation).

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3 years ago

Find x, and then any unknown angles in the quadrilateral.<br> x= ?

sertanlavr [38]

Answer:

x=65

other angle= 165

Step-by-step explanation:

quadrilaterals always have a total of 360 degrees

because of this you can set up an equation and solve

360=90+40+x+(4x-95)

360=130+5x-95

360=35+5x

325=5x

65=x

plug this in to find missing angle

4(65)-95=165

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3 years ago

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2 years ago

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Answer:B

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2 years ago

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