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Ivenika [448]
3 years ago
12

Find the hypotenuse (c) of the right triangle.

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0
<h2><u>Solution</u>:-</h2>

Hypotenuse (x) of the right triangle = \sqrt{7² \: + \: 11²}

Hypotenuse (x) of the right triangle = \sqrt{49 \: + \: 121}

Hypotenuse (x) of the right triangle = \sqrt{170}

Hypotenuse (x) of the right triangle = 13

The hypotenuse (x) of the right triangle is <u>1</u><u>3</u><u> </u><u>m</u>.

<h3>Hence, option (D) <u>1</u><u>3</u><u> </u><u>m</u> is correct. [Answer]</h3>
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Answer:

\dfrac{1}{11}

Step-by-step explanation:

Apply exponent rule:  

\sqrt[n]{a} =a^{\frac{1}{n}}

\implies \sqrt[11]{12}=12^{\frac{1}{11}}

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Answer:

There is no problem stated, but here is the x's for every equations provided:

Step-by-step explanation:

a.) x²+2=36

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