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Leviafan [203]
3 years ago
9

Find the area of a regular heptagon with a side length of 14 units. Use 2 decimal places

Mathematics
1 answer:
Aloiza [94]3 years ago
4 0

Answer:

Area of heptagon = 712.26 square units

Step-by-step explanation:

Given the following data;

Side length = 14 units

A heptagon is a polygon with seven sides.

Mathematically, the area of a heptagon is given by the formula;

Area of heptagon = 3.634a²

Where;

a represents the side length.

Area of heptagon = 3.634 * 14²

Area of heptagon = 3.634 * 196

Area of heptagon = 712.26 square units

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3 years ago
I NEED HELP PICTURE PROVIDED!
Sav [38]
Question 2:
The answer is 21
The two angles are vertically opposite, which makes them equal and also means we can make an equation:
4x - 4 = 3x + 17
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x - 4 = 14
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Question 3:
The answer is 23
Again, the angles are vertically opposite, so we can make them equal each other:
5x - 53 = 3x - 7
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2x - 53 = -7
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3 years ago
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3 years ago
How do you put 3.44 as a mixed number?
miss Akunina [59]
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5 0
3 years ago
Find the missing side length XI. round your answer to the nearest tenth.​
lianna [129]

Answer: XI = 10.35 mm

Step-by-step explanation:

Considering the given triangle XIF, to determine XI, we would apply the sine rule. It is expressed as

a/SinA = b/SinB = c/SinC

Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Likening it to the given triangle, the expression becomes

XI/SinF = XF/SinI = FI/SinX

The sum of the angles in a triangle is 180°. It means that

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F = 180 - (63 + 52)

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Therefore

XI/Sin 65 = 9/Sin 52

Cross multiplying, it becomes

XISin52 = 9Sin65

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0.788XI = 8.154

XI = 8.154/0.788

XI = 10.35

7 0
3 years ago
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