The random sample proportion:
at 90% confidence interval: The Central 90% of any normal distribution is: Z_(α/2) = 1.960
Error = E = ±5% = ±0.05
Applying the normal distribution theory,
= 0.70 ≤ P≤ 0.77(this means that we are 90% confident that the true proportion of jet with wiring problem fall with 0.70 and 0.77, hence there is no need for the airline to conduct further sampling, rather, they should just inspect all the planes)
learn more about probability: brainly.com/question/13604758
21234
A ) The data in this table represents a function.
This function is : f ( x ) = 1/2 x
B ) f 1( 8 ) = 1/2 * 8 = 4 (also from the data in the table)
f 2( 8 ) = 3 * 8 - 10 = 24 - 10 = 14.
Second relation has a greater value when x = 8
C ) f ( x ) = 80
3 x - 10 = 80
3 x = 90
x = 90 : 3
x = 30
Im guessing it'll be C, but im not sure so im sorry if this didnt help
Answer:
t=18 years
Step-by-step explanation:
A year has two semesters, then
n = 2v(t)=p(1+r/2)2t
3875.79 = 1900∗(1+(0.04/2))^2t
2.0398895 = (1+0.042)^2t
Apply natural logarithm on both sides
ln(2.0398895) = ln[(1+0.042)^2t]
Then simplify,
0.712896 = 2t∗ln(1.02)
t = 0.712896 / (2∗ln(1.02))
t=18 years
On your paper, you wrote down a^2+b^2 = c^2 which is the pythagorean theorem
You are on the right track. You'll use this equation. In this case
a = 36
b = 18
c = 43
The value of a and b can be swapped. The value of c is always the longest side.
Let's see if a^2+b^2 = c^2 is true or not
a^2 + b^2 = c^2
36^2 + 18^2 = 43^2
1296 + 324 = 1849
1620 = 1849
The last equation is false so the first equation is false when a = 36, b = 18 and c = 43
We do NOT have a right triangle so we do NOT have a rectangle
Answer: No, the table is not "square" (ie, have right angles at the corners)
