Answer:
<em>The mass of the shotput is 7.37 Kg.</em>
Explanation:
<u>Mechanical Force</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object. If the net force is zero, the object keeps moving at the same speed or keeps at rest (v=0).
A force of 140 N is exerted by a shot-putter on a shotput, which gets an acceleration of 19 m/s^2. We are required to calculate the mass of the shotput.
It can be done by solving the equation for m:
Substituting the given values:
m = 7.37 Kg
The mass of the shotput is 7.37 Kg.
A transverse wave always move perpendicularly from its medium. In the problem the medium is the rope. So when the transverse wave movement is left and right, the perpendicular equivalent movement of the rope is up and down.
Answer:
Constructive interference
Explanation:
Here, the medium is same, same wavelength, same frequency, same amplitude and same direction of propagation.
Let the intensity of waves be I which is same for both
The formula for the net intensity is
where, Ф be the phase difference
So,
Here, IR is maximum so the interference is constructive in nature.
<span>To calculate the density, we must first calculate the volume of the object. For a rectangle, the volume is equal to V=l*w*h. In this case, V=22*13.5*12.5=3712.5 mm^3. Next we have to convert the mm^3 to mL using the conversion factor of 1 mm^3=.001 mL. To get mL, we set up the expression 3712.5 mm^3 * (.001mL/1mm^3) = 3.7125 mL. Finally, to get the density, we know density is mass over volume, so we set the expression p=m/V=2.5g/3.7125mL=.6734 which rounded to 3 significant figures is .673. The answer will be .673</span>