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IceJOKER [234]
3 years ago
8

Show that pair production is not possible without a neighbouring particle that takes part of the momentum.

Physics
1 answer:
egoroff_w [7]3 years ago
3 0

Answer:

By conservation of momentum

Explanation:

By conservation of energy, the photon needs at least the same amount of energy as the energy rest mass of the electron and positron together, which is around 1,02 MeV. But, by conservation of momentum, the electron-positron do not have momentum, while the photon had some. This means that, in order to conserve momentum, we need another neighboring particle, normally an atomic nucleus,  to receive the photon's momentum.

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A theory is a way of explaining observations. true or false.
Natasha_Volkova [10]
I think its true. hope this helps.
5 0
3 years ago
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How significant is air resistance for projectile motion?
miv72 [106K]

Answer:

Air resistance have some significant role in projectile motion if the motion lasts for some time.

Explanation:

  • Air resistance or air drag seems to be important in daily actvities and games like baseball.
  • The trajectory of the projectile with or without air resistance or air drag is totally different.
  • When we neglect air drag, the only acting force is gravity against the motion so the maximum height and range are suppose Hmax and R.
  • Now, when we consider air drag, it is important to notice that there are two forces against the motion of the ball and along the direction of gravity. It seems that both maximum height and range are lesser Hmax'< Hmax and R'<R.
8 0
3 years ago
As viewed from above in this picture, what direction will the current be in the coil of wire that will cause the loop to rotate
Gala2k [10]

Answer:

When viewed from above, the current in the coil should point towards the top-right corner of the picture.

Explanation:

The current in this coil have only two possible directions: clockwise or counter-clockwise. However, since the diagram shows the coil from above, not from a cross-section, just saying clockwise or counter-clockwise might be ambiguous. The statement that the current is directed towards the top-right corner of the picture is equivalent to saying that when viewed from the lower-right corner of this diagram, the current in the coil is moving clockwise.

Note that at the center of this picture, the current is parallel to the magnetic field- there will be no force on the coil at that position. On the other hand, (also when viewed from above,) at the top-right corner and the lower-left corner of the coil, the current in the coil will be perpendicular to the magnetic field. That's where the force on the coil will be the strongest.

With that in mind, apply the right-hand rule to find the direction of the force on the coil in each of the two possibilities.

Assume that when viewed from above, the current is flowing towards the top-right corner of the picture. Consider the wire near the top-right corner of this coil (as viewed above on this picture.) The current will be going into the picture into the magnetic field. By the right-hand rule, the current on the wire near that point should be pointing towards the bottom of this picture. (Point fingers on the right hand in the direction of the current I. Rotate the right hand such that when curling the fingers, they point in the direction of the magnetic field B. The direction of the right thumb should now point in the direction of the force on the wire F.)

Based on the same assumption, the current in the wires near the bottom left corner of this coil will be pointing out of the picture. By the right hand rule, the magnetic force on the coil in that region should be pointing towards the top of this picture. Combing these two forces, the coil would indeed be rotating around the center of this picture in the direction shown in the diagram.

It can also be shown that if the current points towards the bottom left corner of the picture when viewed from above, the coil will be rotating about the center of this picture in the opposite direction.

7 0
3 years ago
a 20 ft shipping container on a cargo ship has a mass of 24000 kg and a volume of 33.2m3. what is the density of the shipping co
Ira Lisetskai [31]

Answer:

722.89

Explanation:

mass=24000kg

volume=33•2

density=?

now,

density=mass/volume

=24000/33•2

=722•89

density=722•89 kg/m^3

3 0
3 years ago
What must be part of a quantitative observation?
inna [77]
a number hope this helps
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