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Katena32 [7]
3 years ago
5

Evaluate the logarithmic function for the given value.

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer:

f(125) = log_{5}(125 ) \\  =  log_{5}( {5}^{3} ) = 3 log_{5}(5 )  = 3(1) =  3

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What is the answer to:
velikii [3]
Weird way to write it but alright! (Sideways) 

19pq^-2 x 5pq^6 = ?

These problems are pretty much single operations between each of the variables / constants. 

So it's like this: 

(19*5)(p*p)(q^-2*q^6) = ?

19*5 is 95.

For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2. 

p*p is p^2

For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this: 

-2 + 6 = 4 
(The two is negative, because the power is negative 2) 

So, q^4. 

Our final answer is all of the combined.... like a so: 

95p^2q^4
3 0
3 years ago
Please help me, just need the answer and thank you!
Triss [41]
Answer to what? I’m confused lol
6 0
3 years ago
Read 2 more answers
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
anita rode her bike for 5.3 kilometers. if she rode her bike 1hour, what would her average speed in kilometers per hour?
pashok25 [27]
How long did she ride it for?

otherwise it would be 5.3 kph
7 0
3 years ago
Father is 20 years older than son. if the sum of their ages is 40 years find their age​
sweet-ann [11.9K]

Answer:

20 is the father's 20 is the son

Step-by-step explanation:

20+20=40

40/2=20

40-20=20

another way:

20:n= 40

40-20=20

20:20=40

4 0
3 years ago
Read 2 more answers
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