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jasenka [17]
3 years ago
9

In the arithmetic sequence, -12, -17, -22, -27... which term has a value of -68?​

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

-68 is not a term in the given sequence

Step-by-step explanation:

The given sequence is -12, -17, -22, -27...

There is a common difference of d=-17--12=-5

The explicit rule for this sequence is f(n)=-12-5(n-1)

Or f(n)=-5n-7

To find the term that has a value of -68 we equate the explicit formula and solve for n.

 -68=-5n-7

 \implies -68+7=-5n

 \implies -61=-5n

n=\frac{61}{5} =12.2

The position should be a natural number.

Since n is a decimal, it tells us that -68 is not a term in the given sequence

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