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3 years ago

Quick question a lot of points help please

Mathematics

1 answer:

dybincka [34]3 years ago

5 0

the right answer to the question is catch me on the root mean square velocity of gas molecule when measured by galvanometer to produce circular egg in the presence of light under blanket.

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1. A translation of function f is f1(x) = b(x – h). It is equivalent to

svetoff [14.1K]

4 will be the correct answer to your question

7 0

3 years ago

Hi I need to know the slope(m) before 11:00 I know the y-intercept(b) is -3

Alexxandr [17]

Answer:

slope is 2/3

Step-by-step explanation:

y=mx + b where m is the slope

6 0

2 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

The following graph represents the cost and revenue functions for custom made computers. How many computers have been sold at th

svetlana [45]

The answer is A) 12
Hope this helped
Pls give me brainlest

5 0

3 years ago

Read 2 more answers

Multiply: x (x^2+2x+4) and -2 (x^2+2x+4) Combine like terms. Final Answer:

natulia [17]

Answer:

x^3-8

Step-by-step explanation:

x^3+2x^2+4x + -2x^2-4x-8

+2x^2 and -2x^2 cancel out

+4x and -4x cancel out

5 0

3 years ago