Ask question

Ask question

All categories

2 years ago

10

If the world's population increased exponentially from billion in 1998 to billion in 2008 and continued to increase at the same

percentage rate between 2008 and 2012, calculate what the world's population would have been in 2012. Round your answer to two decimal places.

1 answer:

Gelneren [198K]2 years ago

7 0

Answer:

The answer is "7.122 billion"

Step-by-step explanation:

Please find the complete question in the attached file.

Using formula:

$\to y=Ce^{kt}$

$C=5.937\\\\y=6.771\\\\t=10\\\\ k=?6.771=5.937e^{10k}\\\\1.1405=e^{10k}\\\\\ln(1.1405)={10\ k}\\\\0.013={k}\\\\$

So,

$\to y=5.937e^{.013t}\\\\$

when it becomes $2012, \ t=14$ so plug the value into the formula

$\to y= 5.937e^{.013(14)} =7.122 \ billion$

You might be interested in

What is an equation of the line that passes through the points (4, 4) and (8, 1)?

geniusboy [140]

Answer: y = -3/4x + 7

Step-by-step explanation:

first find slope:

y2-y1 / x2 - x1

1-4 / 8-4

-3/4

now just plug the slope (m) into the equation of a line using one of the points to find the y intercept

ill use (8,1)

1 = (-3/4)(8) + b

now solve :)

1 = -6 + b

7 = b

so now plug in the slope and the y intercept into the slope intercept form to find the equation of the line

y = -3/4x + 7

3 0

2 years ago

I need help on number 2

Nina [5.8K]

9514 1404 393

Answer:

a. 405

b. -2

c. 5

d. 43

Step-by-step explanation:

I don't like doing arithmetic any more than you do, so I let a calculator do it for me. A spreadsheet works well for this, too. The function values are shown in the attachment.

Put the function argument where the variable is and do the arithmetic.

a. h(4) = 5·3^4 = 405

b. d(2) = 7 -9(2 -1) = -2

c. h(0) = 5·3^0 = 5

d. d(-3) = 7 -9(-3 -1) = 43

7 0

2 years ago

100 POINTS HELP ASAP Linear Combination

notka56 [123]

Answer:

1) $x=\dfrac12$

2) $n = -3 \ \ \textsf{and} \ \ m = -4$

3) see below

4) A: 0 = 1

Step-by-step explanation:

<u>Question 1</u>

$15-0.5(4x-2)+4x=17$

$\implies 15-2x+1+4x=17$

$\implies 2x+16=17$

$\implies 2x=1$

$\implies x=\dfrac12$

<u>Question 2</u>

$\textsf{rearrange} \ n=m+1 :$

$\implies -m=-n+1$

$\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\$

$\implies0=n+3$

$\implies n=-3$

$\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:$

$\implies m=-3-1$

$\implies m=-4$

<u>Question 3</u>

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

<u>Question 4</u>

$3j=k$

$k=3j+1$

$\textsf{rearrange} \ 3j=k :$

$\implies -k=-3j$

$\textsf{add equations}\ -k=-3j \ \ \textsf{and}\ \ k=3j+1:$

$\implies 0=1$

Solution = A

6 0

2 years ago

Un empresario contrata a 16 obreros para realizar un trabajo y a cada uno le paga 385 €. Si el empresario quiere ganar 892 €. ¿C

OverLord2011 [107]

Answer:

7052€

Step-by-step explanation:

Si el empresario quiere gana 892€, primero tiene que encontrar el valor total a pagar a los 16 obreros y sumarle a ese valor la ganancia que quiere obtener:

Valor total a pagar a los obreros: 385€*16= 6160€

Valor a cobrar por el trabajo: 6160+892= 7052€

De acuerdo con esto, si el empresario quiere ganar 892 €, debe cobrar 7052€ por el trabajo.

5 0

3 years ago

Express (16^3)^1/2 <br> in simplest radical form.

Rufina [12.5K]

Answer:

I assume you mean 16^(1/3) i.e. the cube root of 16

I am also assuming you mean the real cube root because, as you may know, every non-zero real number has three cube root - one real and two complex conjugates.

Since 16 = 8 x 2 and 8 = 2³ then (2³ x 2)^1/3 = (2³)^1/3 x 2^1/3 = 2 x 2^1/3

You might check that the cube root of 16 is about 2.52 which is twice the cube root of 2

Step-by-step explanation:

6 0

2 years ago