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viktelen [127]
2 years ago
10

If the world's population increased exponentially from billion in 1998 to billion in 2008 and continued to increase at the same

percentage rate between 2008 and 2012, calculate what the world's population would have been in 2012. Round your answer to two decimal places.
Mathematics
1 answer:
Gelneren [198K]2 years ago
7 0

Answer:

The answer is "7.122 billion"

Step-by-step explanation:

Please find the complete question in the attached file.

Using formula:

\to y=Ce^{kt}  

C=5.937\\\\y=6.771\\\\t=10\\\\ k=?6.771=5.937e^{10k}\\\\1.1405=e^{10k}\\\\\ln(1.1405)={10\ k}\\\\0.013={k}\\\\

So,  

\to y=5.937e^{.013t}\\\\

when it becomes 2012, \ t=14 so plug the value into the formula  

\to y= 5.937e^{.013(14)} =7.122 \ billion

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As an estimation we are told 5 miles is 8km convert 30<br> miles to km
Nutka1998 [239]

Find the scale:

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2 years ago
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Can somebody please walked through this, I'm so confused and I have a test in 6 hours...
erastova [34]

Answer:

Q3: x = 4, y = 4, z = 4

Q4: x = 6, y = 0, z = -4

Step-by-step explanation:

Question 3: Simultaneous equations requires us to solve for x, y and z.

Since all three equations have a z in them, I will first solve for z.

Substitute in the first and third equation into the second equation.

First equation: x = 5z - 16

Second Equation: -4x + 4y - 5z = -20

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Substituting in x = 5z - 16 and y = -z + 8 for the x and y in the second equation.

-4(5z - 16) + 4(-z + 8) - 5z = -20

Expand

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Simplify and solve for z by putting all the numbers on one side and all the z's on the other side of the equals

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Substitute in this z value into the first and last equation and then solve for x and y

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And

y = -z + 8

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Rearrange them so that the letters are on one side and numbers on the other side.

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Second equation: z + 2y = -4

I will choose to eliminate the y (You can choose either or)

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2(y + 6z = -24)

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