Please help me thanks

Which ordered pair is a solution of the equation? y = -3x-4.

geniusboy [140]

Answer:

B. Only (-3,5)

Step-by-step explanation:

1. Plug in the x values from the answer choices and see if it gives you the y-value in the answer choices.

A. y=-3(-2) - 4

= 6 - 4

y = 2

The ordered pair for answer A is (-2,4) where the y-value is 4. Well, when you plugged in -2 for x you got 2, not 4. So A can't be the right answer.

B. y=-3(-3) - 4

= 9- 4

y = 5

The y-value in this ordered pair (-3,5) is indeed 5, so this answer holds true.

Therefore, the answer is B because it is the only ordered pair that has the correct solution.

8 0

3 years ago

A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seco

OLEGan [10]

Answer:

2.02

2.15

0.13

Step-by-step explanation:

Fastest time = smallest value = 2.02 secs

Slowest time = largest value = 2.15 secs

Range = largest value - smallest value = 2.15 - 2.02 = 0.13 secs

4 0

3 years ago

Read 2 more answers

The shuttle bus from your parking lot and your office building operates on a 15 minute schedule. You arrive at the parking lot a

mylen [45]

Answer:

(a) The standard deviation of your waiting time is 4.33 minutes.

(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.

Step-by-step explanation:

Let X = the waiting time for the bus at the parking lot.

The random variable X is uniformly distributed with parameters a = 0 to b = 15.

The probability density function of X is given as follows:

$f_{X}(x)=\frac{1}{b-a};\ a$

(a)

The standard deviation of a Uniformly distributed random variable is given by:

$SD=\sqrt{\frac{(b-a)^{2}}{12}}$

Compute the standard deviation of the random variable X as follows:

$SD=\sqrt{\frac{(b-a)^{2}}{12}}$

$=\sqrt{\frac{(15-0)^{2}}{12}}$

$=\sqrt{\frac{225}{12}}$

$=\sqrt{18.75}\\=4.33$

Thus, the standard deviation of your waiting time is 4.33 minutes.

(b)

The value representing 2 standard deviations is:

$X=2\times SD=2\times4.33=8.66$

Compute the value of P (X > 8.66) as follows:

$P(X>8.66)=\int\limits^{10}_{8.66} {\frac{1}{15-0}}\, dx\\$

$=\frac{1}{15}\times \int\limits^{10}_{8.66} {1}\, dx\\$

$=\frac{1}{15}\times |x|^{15}_{8.66}\\$

$=\frac{15-8.66}{15}\\$

$=0.4227$

Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.

4 0

3 years ago

Isaiah brought two dozen donuts to a class party. Half of the donuts had vanilla frosting with sprinkles, 2 had strawberry frost

Andrej [43]

Answer: 22

Step-by-step explanation:

Two dozen equals 24, divide it in half leaves 12 vanilla sprinkle doughnuts

the remaining 12 minus the 2 strawberry cream equals 10 chocolate sprinkles

add the 10 chocolate plus 12 vanilla to get 22

5 0

3 years ago

Need help asap im not good at math

wolverine [178]

g(x):

flip f(x) over x-axist and next translate 2 units down.

Look at the picture.

<h3>Therefore your answer is: B. g(x) = -x² - 2</h3>

Translations

y = f (x) + m up m units

y = f (x) - m down m units

y = f (x + m) left m units

y = f (x - m) right m units

Stretches/Shrinks

y = n · f (x) stretch vertically by a factor of n

y = 1/n · f (x) shrink vertically by a factor of m (stretch by 1/n)

y = f (1/n x) stretch horizonally by a factor of n

y = f (nx) shrink horizontally by a factor of n (stretch by 1/n)

Reflections

y = - f (x) reflect over x-axis (over line y = 0)

y = f (- x) reflect over y-axis (over line x = 0)

x = f (y) reflect over line y = x

3 0

3 years ago