So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!
f(2) This means that x is 2, so you plug in 2 for x in the equation
![f(x)=\frac{1}{3} (4^x)](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B3%7D%20%284%5Ex%29)
![f(2)=\frac{1}{3}(4^2)](https://tex.z-dn.net/?f=f%282%29%3D%5Cfrac%7B1%7D%7B3%7D%284%5E2%29)
![f(2)=\frac{1}{3} (16)](https://tex.z-dn.net/?f=f%282%29%3D%5Cfrac%7B1%7D%7B3%7D%20%2816%29)
![f(2)=\frac{16}{3}](https://tex.z-dn.net/?f=f%282%29%3D%5Cfrac%7B16%7D%7B3%7D)
Your answer is D
Answer:
if the diameter of the circle is 25, then the radius will be 12.5.
A=3.14(12.5)2 --> 490.9m^2
C= 2*3.14(12.5)---> 78.5 m