The height of the isosceles triangle is 8.49 inches.
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How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
brainly.com/question/2217700
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Inverse property of multiplication.
To add or subtract with powers, both the variables and the exponents of the variables must be the same. You perform the required operations on the coefficients, leaving the variable and exponent as they are.
Answer: x = 16
Step-by-step explanation:
If RQ is the bisector, that means the angle is cut in half. Therefore angles PRQ and QRS are equal to each other.
4x+6 = 7x-42
subtract 7x from both sides
-3x+6 = -42
subtract 6 from both sides
-3x = -48
divide both sides by -3
x = 16
