First you must add the same numbers together, for instance, you wouldn't add 4y with 4 you have to add it with another number that is just like it, for instance 4y and 9y they are the same, so you can add them. So let's get to the problem now:
5y(2y-3)=(2y-3)
5y*2y=10y
(10y-3)=(2y-3)
You can do nothing to the other side because there are no numbers, that are the same.
1) -3x -3 -7x = 17
• start by grouping so add -3x and -7x which gives you -10x
• 10x -3 (+3) = 17 +3 = 20 add 3 on both sides)
• 10x (/10) = 20/ 10 = 2
1) x = 2
2) 10x -6 (+6) = 24 + 6 = 30
• 10x (/10) = 30/ 10 = 3
2) x = 3
3) -4 (+4) -5x = -39 +4 = -35
• -5x (/-5) = -35/ -5 = 7
3) x = 7
4) 3x - 5 > 10
this one i don’t understand, is there a typo maybe ?
5) -5x + x + 16 = -3 you can put a 1 to hold the place of x to make it 1x
• (-5x + 1x) + 16 = -3
• -4x + 16 (-16) = -3 -16 = -19
• -4x (/-4) = -19/ -4 = 4.75 or 4 3/4
5) x = 4.75
Answer:
-13x^2 + 6x + 11
Step-by-step explanation:
Just subtract the numbers that are similar (i.e. -5x^2 - 8x^2)
Answer:
It's C, REVIEW THE EVALUATIVE MODIFIERS
Step-by-step explanation: