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2 years ago

Solve 1 And 2 Step Equations.

Mathematics

1 answer:

masha68 [24]2 years ago

7 0

Answer:

ksbdksvudkdbckx skxid SORRRYYYYY BUT I NEED POINTSSSSS :(

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I'm very confused on how to solve this problem, can anyone please help? Thanks!

Pepsi [2]

Answer:

Step-by-step explanation:

DC = 16 and

DB = 30 so

CB = 14

DB = 30 and

EB = 49 so

EB = 19

5 0

3 years ago

What is the sum of x2-3x+7 and 3x2+5x-9

Ghella [55]

(x² - 3x + 7) + (3x² + 5x - 9)
(x² + 3x²) + (-3x + 5x) + (7 - 9)
4x² + 2x - 2

5 0

3 years ago

Solve for X: 5x + 15 = 28

rjkz [21]

-15 both sides and then it’s will be
5x = 13 then u divide both sides over 5 and the answer will be ( X=2.6 )

4 0

2 years ago

Find the area and perimeter 6cm 2cm 5cm 5cm 9cm

Basile [38]

Answer:

Perimiter= 27

Step-by-step explanation:

It equals that, because in order to find the perimeter of something, you just add all of the sides together. I don't know how to do the area, but I'm sure you'll be able to find how on google. I hope this helped in some way

4 0

3 years ago

The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the

Taya2010 [7]

Answer:

$L_1 = 4$

And $L_2 = 3 +4 = 7$

Step-by-step explanation:

For this case we assume that for the first square we have the following dimensions:

$A_1 = L^2_1$

And we know that:

$L_2 = 3 + L_1$

And the area for the second square would be:

$A_2 = L^2_2 = (3+L_1)^2 = 9 + 6L_1 + L^2_1$

And we know that the sum of areas is 65 so then we have this:

$A_1 + A_2 = 65$

And replacing we got:

$L^2_1 + 9 + 6L_1 + L^2_1 = 65$

$2L^2_1 +6L_1 - 56=0$

We can divide the last expression by 2 and we got:

$L^2_1 + 3L_1 -28=0$

And we can factorize the last expression like this:

$(L_1 + 7) (L_1 -4) =0$

And we have two solutions for $L_1$ and we got:

$L_1 = 4, L_1 = -7$

Since the length can't be negative we have this:

$L_1 = 4$

And $L_2 = 3 +4 = 7$

4 0

3 years ago

Read 2 more answers