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3 years ago

Find the perimeter.

Mathematics

2 answers:

Ulleksa [173]3 years ago

7 0

Answer:

36.8 in

Step-by-step explanation:

Perimeter is the sum of length of all sides of the figure

Perimeter=8.2+10.8+4.5+7.1+2.8+3.4=36.8

galina1969 [7]3 years ago

5 0

Answer:

36.8

Step-by-step explanation:

Perimeter is the addition of each side.

8.2 + 4.5 + 7.1 + 10.8 + 3.4 + 2.8

^ ^

12.7 + 7.1

19.8 + 10.8

30.6 + 3.4

34 + 2.8

36.8

Hope this helped.

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Marian can weed a garden in 3 hrs. Robin can weed the same garden in 4 hrs. If they work together, how long will the weeding tak

irina1246 [14]

Answer:

The answer would be 12

Step-by-step explanation:

because all u have to do is multiply

8 0

3 years ago

What is the 8th term of the geometric sequence a2 = 20 and r = 5

algol [13]

Answer:

8th term of geometric sequence is 312500

Step-by-step explanation:

Given : $a_2=20$ and common ratio (r) = 5

We have to find the 8th term of the geometric sequence whose $a_2=20$ and common ratio (r) = 5

Geometric sequence is a sequence of numbers in which next term is found by multiplying by a constant called the common ratio (r).

$a_n=ar^{n-1}$ ......(1)

where $a_n$ is nth term and a is first term.

For given sequence

a can be find using $a_2=20$ and r = 5

Substitute in (1) , we get,

$a_2=ar^{2-1}$

$\Rightarrow 20=a(5)$

$\Rightarrow a=4$

Thus, 8th term of the sequence denoted as $a_8$

Substitute n= 8 in (1) , we get,

$a_8=ar^{8-1} \\\\a_8=(4)r_{7} \\\\a_8=4(5)^7=4 \times 78125=312500$

Thus 8th term of geometric sequence is 312500

8 0

3 years ago

Evaluate the determinant for the following matrix 1, 4, 4, 5, 2, 2, 1, 5, 5

Oliga [24]

Answer:

Step-by-step explanation:

The determinant of this matrix is zero (0).

6 0

3 years ago

A small bag of flavor weighed 13 ounces. A large bag was 5 percent heavier.How much does the large bag weigh?

Novay_Z [31]

13+5=18
The large bag would be 18 because you have to add 5 more ounces than 13

5 0

4 years ago

A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d

Alenkasestr [34]

Answer:

μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

Distance 1:

- Ff*d₁ = Ef - Ei

⇒ - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ

⇒ - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ (I)

Distance 2:

- Ff*d₂ = Ef - Ei

⇒ - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒ μ*g*d₂ = 0.5*v² (II)

If we apply (I) + (II)

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ (III)

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁ ⇒ vf² = 2*g*Sin θ*d₁ = v²

then (from the equation III) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒ μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒ μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK ⇒ - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁ ⇒ d₂ = Sin θ*d₁ / μ

3 0

3 years ago