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3 years ago

What are the solutions of ×^2=8-5×?

Mathematics

1 answer:

yaroslaw [1]3 years ago

7 0

Answer:

x=8 & x=3

Step-by-step explanation:

We want to get the (x)s all on one side.

add 5x to each side

${x}^{2} + 5x = 8$

Since x^2 is x•x and 5x is 5•x then we can change the formula to

x(x+5)=8

then seperate that

x=8

x+5=8

subtract 5 from each side

x=3.

The solutions are 8 and 3.

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10: A stadium brings in $16.25 million per year. It pays football-related expenses of $13.5 million and stadium expenses of $2.7

Oksanka [162]

The stadium brings is $16,250,000 per year. (Revenue)

Football-related expenses equal $13,500,000 per year. (Cost)

Stadium expenses equal $2,700,000 per year. (Cost)

Profit margin is calculated by dividing net profit with the revenue.

To get net profit, subtract the revenue with the total cost.

First, add the two costs together to get the total cost.

$13,500,000 + $2,700,000 = $16,200,000 (total cost)

$16,250,000 (revenue) - $16,200,000 (total cost) = $50,000 (net profit)

$50,000 (net profit) ÷ $16,250,000 (revenue) = 0.0030769

To turn that decimal into a fraction, multiply it with 100

0.0030769 x 100 = 0.30769%

Round this up to 0.308%

The stadium's current profit margin is 0.308%

5 0

3 years ago

If T(n) = 2n - 7 what is the 5th term

nadezda [96]

Plug in n = 5 to find the 5th term

T(5) = 2(5) - 7
T(5) = 10 - 7
T(5) = 3

The 5th term is 3.

3 0

3 years ago

Read 2 more answers

What is the median for the boys plot?

ollegr [7]

Answer:

Step-by-step explanation:

first you put the numbers in order from least to greatest

1,1,1,1,2,2,2,4,12,13,15,15,15,16,16

next find the middle number(s)

1,1,1,1,2,2,2,<em>4</em>,12,13,15,15,15,16,16

the middle number is your median

*if you have 2 middle numbers just add the then divide it by 2 to find the median

7 0

3 years ago

Dylan keeps a fitness journal. Each week he runs 18 miles and swims 2 miles. What rules can you use to complete the table to sho

Kobotan [32]

Where are the boxes?

18/2 = 9

1st box - 18 : 2

2nd box - 36 : 4

3rd box - 72 : 8

etc . . .

6 0

3 years ago

On a huge site in San-Diego the whole new street of houses was constructed. To put the numbers on all new buildings the plates w

Papessa [141]

<h2>There are 45 houses on the left and require 95 plates, while there are 44 houses on the right and require 94 plates</h2>

Step-by-step explanation:

Houses are numbered from 1 to 99. So, there are 99 houses. Odd-numbered houses are on the left. So, there are 50 houses on the left, while there are 49 houses on the right.

For houses on left : The houses are numbered 1, 3, 5, 7, 9, 11, 13..... 97, 99

So 5 houses( 1, 3, 5, 7, 9) require only one plate for numbering, while the remaining 45 houses require 2 plates each. So total number of plates = $5\textrm{x}1+45\textrm{x}2$ = $95$ plates.

For houses on right : The houses are numbered 2, 4, 6, 8, 10, 12, 14.... 96, 98

So 4 houses( 2, 4, 6, 8) require only one plate for numbering, while the remaining 45 houses require 2 plates each. So total number of plates = $4\textrm{x}1+45\textrm{x}2$ = $94$ plates.

∴ There are 45 houses on the left and require 95 plates, while there are 44 houses on the right and require 94 plates.

8 0

3 years ago