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xz_007 [3.2K]
2 years ago
9

Compare each set of rational numbers.​

Mathematics
1 answer:
leonid [27]2 years ago
5 0

Answer:

rrrrrrr

Step-by-step explanation:

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7x + 2y = -1<br> 3x – 4y = 19
jeka94

Answer:  Y = - 4 & x = 1

Step-by-step explanation:

Systems of linear equations: We will solve this using substitution but you can use 2 more ways.

7x + 2y = -1

2x - 4y = 19

Leave X  alone first: -------------------

10x - 2y = 18

10x/10 = 18 + 2y/10

x = 9/5 + y/5

Solve for y:

7(9/5 + y/5) + 2y = -1

63/5 + 7y/5 + 2y - 1

63/5 + 7y/5 = 10y/5 = -1

63/5 + 17y/5 = -1 (-5/5)

17y/5 = -68/5 (cancel the 5)

y = -68/17

y = - 4 (Your Answer)

7x + 2(- 4) = -1

7x + (-8) = -1

7x = 7

x =   1

CHECK=

7(1) + 2(-4) = -1

7+ (-8) = -1.

-1=-1

7 0
3 years ago
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Rain fell at the steady rate of 2 inches every 3 hours.
Mamont248 [21]

what is your question then?

8 0
3 years ago
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Four years ago, Alex was twice as old as Jake. Four years from now,Jake will be 3/4 of Alex’s age. How old is Alex?
Vanyuwa [196]

Answer:Four years ago, Alex was twice as old as Jake. Four years from now, Jake will be 3/4 of Alex's age. How old is Alex? - Answer: 12.

Step-by-step explanation:

8 0
3 years ago
I need the answer quick pls I have a test
miss Akunina [59]

.........................

5 0
3 years ago
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What is the value of x for log6(5x) + log6(2)=5
Igoryamba

\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_6(5x)+\log_6(2)=5\implies \log_6(5x\cdot 2)=5\implies \log_6(10x)=5 \\\\\\ 6^{ \log_6(10x)}=6^5\implies 10x=6^5\implies x = \cfrac{6^5}{10}\implies x = \cfrac{3888}{5}\implies x = 777.6

8 0
3 years ago
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