3 years ago

Solve the inequality 2ax-3<4x+5a for all possible values of the parameter a

Mathematics

1 answer:

olga_2 [115]3 years ago

5 0

Answer:

Step-by-step explanation:

2ax−3<4x+5a

Step 1: Add -5a to both sides.

2ax−3+−5a<5a+4x+−5a

2ax−5a−3<4x

Step 2: Add 3 to both sides.

2ax−5a−3+3<4x+3

2ax−5a<4x+3

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Hi there!

»»————-　★　————-««

I believe your answer is:

"Isolate the variable using inverse operations."

»»————-　★　————-««

Here’s why:

To solve for a variable, we would have to isolate it on one side.

To isolate it, we would use inverse operations on both sides on the equation until the variable is isolated.

There are no like terms in the given equation.

⸻⸻⸻⸻

$\boxed{\text{Solving for 'z'...}}\\\\\frac{z}{6} = 36\\-------------\\\rightarrow (\frac{z}{6})6 = (36)6\\\\\rightarrow \boxed{z = 216}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

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