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gogolik [260]
3 years ago
10

Solve the inequality 2ax-3<4x+5a for all possible values of the parameter a

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

Step-by-step explanation:

2ax−3<4x+5a

Step 1: Add -5a to both sides.

2ax−3+−5a<5a+4x+−5a

2ax−5a−3<4x

Step 2: Add 3 to both sides.

2ax−5a−3+3<4x+3

2ax−5a<4x+3

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Is the line segment 4x+2y=0 parallel?
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Answer:

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Step-by-step explanation:

1) 2a-3b divided by 6

(2a-3b)/6 = (2a/6) - (3b)/6 = (a/3) - (b/2)

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8 0
3 years ago
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