1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zheka24 [161]
2 years ago
9

Find the area of the trapezoid

Mathematics
1 answer:
Shalnov [3]2 years ago
7 0

Answer: 8

Step-by-step explanation: so we can count the middle four, then the sides are basically two triangles that are the same, so we put them together and you get 4 more, so 4 plus 4 is 8

You might be interested in
Draw a set of objects where you can find a fractional part of the group using the total number of objects and by using subgroups
skad [1K]
The answer is attached
Download docx
8 0
3 years ago
A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the
Vedmedyk [2.9K]
(a) Using Newton's Law of Cooling, \dfrac{dT}{dt} = k(T - T_s), we have \dfrac{dT}{dt} = k(T - 75) where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get \dfrac{dT}{T - 75} = k dt. Integrate both sides to get \ln|T - 75| = kt + C.

Since T(0) = 185, we solve for C:
|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110
So we get \ln|T - 75| = kt + \ln 110. Use T(30) = 150 to solve for k:
\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)

So

\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t}  \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}

But choose Positive because T > 75. Temp of turkey can't go under.

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)}  = 136.929 \approx 137{}^{\circ}F

(b)

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30}  \\
100 = 75 + 110(15/22)^{t/30}   \\
25 = 110(15/22)^{t/30}  
\frac{25}{110} = (15/22)^{t/30}   \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22)  \approx 116\ \mathrm{min}

Dogs of the AMS.
4 0
3 years ago
Which of the following statements must be true about this diagram
serg [7]
A B D and F must be true
7 0
2 years ago
Read 2 more answers
The heights of 500 students at a local school were recorded and found to be approximated by the normal curve below. Which
Sunny_sXe [5.5K]

Answer:

option C.

Step-by-step explanation:

The given graph is the bell shaped graph.

From the graph we can observe that the peak is at 69.

So, the mean of the data is = 69 .

Standard deviation is the deviation of the graph from the mean value.

 =  72-69 = 3

Hence, the standard deviation is equal to 3.

So, the correct answer is option C.

5 0
2 years ago
a discounted concert ticket costs $14.50 less than the original price p.You pay $53 for a discounted ticket.Write an equation th
Ahat [919]

Answer:

$53.00 + $14.50

= 67.50

Make sure to leave a good review if it helped you

-Adan


7 0
3 years ago
Other questions:
  • Simplify ( 1/2A + 1/2B )^2
    11·2 answers
  • What is the answer for 3k+16=5k. Please show work.
    7·2 answers
  • I need help with this
    7·1 answer
  • Write two word sentences for the equation r/0.2=40​
    7·1 answer
  • Most complicated and written out explanation for 1 plus 1 can get 20 points and brainliest.
    6·1 answer
  • Use the parent function f(x) = x2 to fill in the blanks.
    8·1 answer
  • Michael practiced his harmonica 3 times as long as Timothy did. Michael practiced for 126 minutes. Write an equation that repres
    8·2 answers
  • Solve and check the equation.<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B10%7D%3D%5Cfrac%7B5x%7D%7B7%7D%20-43" id="TexFor
    9·1 answer
  • I subtract 3 from a certain number, multiply the result by 5 and then add 9
    13·2 answers
  • Construct the indicated confidence interval for the population mean mu.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!