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Slav-nsk [51]
2 years ago
9

Scientific research on popular beverages consisted of 70 studies that were fully sponsored by the food industry, and 30 studies

that were conducted with no corporate ties. Of those that were fully sponsored by the food industry, 15 % of the participants found the products unfavorable, 23 % were neutral, and 62 % found the products favorable. Of those that had no industry funding, 38 % found the products unfavorable, 16 % were neutral, and 46 % found the products favorable.a. What is the probability that a participant selected at random found the products favorable?
b. If a randomly selected participant found the product favorable, what is the probability that the study was sponsored by the food industry?
c. If a randomly selected participant found the product unfavorable, what is the probability that the study had no industry funding?
Mathematics
1 answer:
elixir [45]2 years ago
8 0

Answer:

a. 0.26

b. 0.7

c. 0.38

Step-by-step explanation:

For a)

For sponsored studies: 62 %  found the products favorable. The percentage is 0.62.

For non-sponsored studies 46% found the products favorable. The percentage is 0.46

Total probability = P(A) × P (B)

                           = 0.46 × 0.62

                           = 0.2604

For b)

Probability for the food industry = 0.7

For c) 1 - ( 0.62) = 0.38

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landon wants to show that the product of rational numbers is always a rational number. complete his work and explanation by fill
lubasha [3.4K]

Multiply <u>√2</u> by <u>√72</u>. The product is a <u>rational</u> number because <u>√144</u> can be simplified to an integer.

Step-by-step explanation:

As Landon has to prove that two product of two rational numbers, he has to choose two rational numbers from the list and then multiply and show that the product is also a rational number.

Let us define the rational numbers first

A number that can be written in the form of p/q where p,q are integers and q is not equal to zero, is called a rational number.

From the give =n list of rational numbers

Taking

√2 and √72

\sqrt{2} * \sqrt{72}\\=\sqrt{2*72}\\=\sqrt{144}\\=12\\=\frac{12}{1}

As we can see that the product of √2 and √72 is 12 which is also a rational number.

So,

Multiply <u>√2</u> by <u>√72</u>. The product is a <u>rational</u> number because <u>√144</u> can be simplified to an integer.

Keywords: Rational numbers, Product

Learn more about rational numbers at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

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A recipe for pancakes calls for 3/4 cup of milk. How much milk will you need if you make 1/2 of the recipe?
OlgaM077 [116]

1/2 of 3/4 which is 3/8 cup of milk


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ASAP 30 + Brainliest <br><br> Please only solve 2 - 5
hichkok12 [17]

<u>QUESTION 2a</u>


We want to find the area of the given right angle triangle.


We use the formula

Area=\frac{1}{2}\times base\times height

The height of the triangle is =a cm.

The base is 12cm.


We substitute the given values to obtain,


Area=\frac{1}{2}\times 12\times a cm^2.

This simplifies to get an expression for the area to be

Area=6a cm^2.





<u>QUESTION 2b</u>


The given diagram is a rectangle.


The area of a rectangle is given by the formula

Area=length \times width


The length of the rectangle is l=7cm and the width of the rectangle is w=ycm.


We substitute the values to obtain the area to be


Area=7 \times y


The expression for the area is

Area=7y


<u>QUESTION 2c.</u>


The given diagram is a rectangle.


The area of a rectangle is given by the formula

Area=length \times width


The length of the rectangle is l=2x cm and the width of the rectangle is w=4 cm.


We substitute the values to obtain the area to be


Area=2x \times 4


The expression for the area is

Area=8x


<u>QUESTION 2d</u>


The given diagram is a square.

The area of a square is given by,

Area=l^2.


where l=b m is the length of one side.


The expression for the area is

Area=b^2 m^2


<u>QUESTION 2e</u>

The given diagram is an isosceles triangle.


The area of this triangle can be found using the formula,

Area=\frac{1}{2}\times base\times height.

The height of the triangle is 4cm.


The base of the triangle is 6a cm.


The expression for the area is

Area=\frac{1}{2}\times 6a \times 4cm^2


Area=12a cm^2


<u>QUESTION 3a</u>

Perimeter is the distance around the figure.

Let P be the perimeter, then

P=x+x+x+x

The expression for the perimeter is

P=4x mm


<u>QUESTION 3b</u>

The given figure is a rectangle.


Let P, be the perimeter of the given figure.

P=L+B+L+B


This simplifies to

P=2L+2B

Or

P=2(L+B)


<u>QUESTION 3c</u>

The given figure is a parallelogram.

Perimeter is the distance around the parallelogram

Perimeter=3q+P+3q+P

This simplifies to,


Perimeter=6q+2P

Or

Perimeter=2(3q+P)



<u>QUESTION 3d</u>

The given figure is a rhombus.

The perimeter is the distance around the whole figure.


Let P be the perimeter. Then

P=5b+5b+5b+5b


This simplifies to,

P=20b mm


<u>QUESTION 3e</u>

The given figure is an equilateral triangle.

The perimeter is the distance around this triangle.

Let P be the perimeter, then,

P=2x+2x+2x


We simplify to get,


P=6x mm


QUESTION 3f

The figure is an isosceles triangle so two sides are equal.


We add all the distance around the triangle to find the perimeter.


This implies that,


Perimeter=3m+5m+5m


Perimeter=13m mm



<u>QUESTION 3g</u>

The given figure is a scalene triangle.

The  perimeter is the distance around the given triangle.

Let P be the perimeter. Then

P=(3x+1)+(2x-1)+(4x+5)


This simplifies to give us,


P=3x+2x+4x+5-1+1


P=9x+5


<u>QUESTION 3h</u>

The given figure is a trapezium.

The perimeter is the distance around the whole trapezium.

Let P be the perimeter.

Then,

P=m+(n-1)+(2m-3)+(n+3)


We group like terms to get,

P=m+2m+n+n-3+3-1

We simplify to get,

P=3m+2n-1mm


QUESTION 3i

The figure is an isosceles triangle.

We add all the distance around the figure to obtain the perimeter.

Let P be the perimeter.


Then P=(2a-b)+(a+2b)+(a+2b)


We regroup the terms to get,

P=2a+a+a-b+2b+2b

This will simplify to give us the expression for the perimeter to be

P=4a+3bmm.


QUESTION 4a

The given figure is a square.


The area of a square is given by the formula;

Area=l^2

where l=2m is the length of one side of the square.


We substitute this value to obtain;

Area=(2m)^2


This simplifies to give the expression of the area to be,

Area=4m^2


QUESTION 4b

The given figure is a rectangle.


The formula for finding the area of a rectangle is

Area=l\times w.

where l=5a cm is the length of the rectangle and w=6cm is the width of the rectangle.

We substitute the values into the formula to get,

Area =5a \times 6


Area =30a cm^2


QUESTION 4c


The given figure is a rectangle.


The formula for finding the area of a rectangle is

Area=l\times w.

where l=7y cm is the length of the rectangle and w=2x cm is the width of the rectangle.

We substitute the values into the formula to get,

Area =7y \times 2x

The expression for the area is

Area =14xy cm^2


QUESTION 4d

The given figure is a rectangle.


The formula for finding the area of a rectangle is

Area=l\times w.

where l=3p cm is the length of the rectangle and w=p cm is the width of the rectangle.

We substitute the values into the formula to get,

Area =3p \times p

The expression for the area is

Area =3p^2 cm^2




See attachment for the continuation


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Answer:

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Step-by-step explanation:

The function shows a point at 2 where x = 0.

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