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Scorpion4ik [409]
3 years ago
11

ATTENTION

Mathematics
1 answer:
finlep [7]3 years ago
3 0

Here!

<h2>The answer is Option A!</h2>

(x + 2 \sqrt{3} i)(x - 2 \sqrt{3}i )

<h3>Why so??</h3>

Let's see what complex numbers are!

(x + 2  \sqrt{3 }i  )(x - 2 \sqrt{3}i ) \\  =  {x}^{2}  - 2 \sqrt{3} x + 2 \sqrt{3} x -  {(2 \sqrt{3} i)}^{2}  \\  =  {x}^{2}  -  {(2 \sqrt{3}i) }^{2}

Now we know,

{i}^{2}  =  - 1

So!

=  {x}^{2}  - 12 \times(  - 1)

=  {x}^{2}  + 12

And thus we get the answer!

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Use the area to find the radius. If you could include steps that’ll be very helpful :)
Marizza181 [45]

Answer:

Radius = 13 m

Step-by-step explanation:

Formula for area of circle is given as:

A = \pi {r}^{2}  \\  \\  \therefore \: 169\pi \: = \pi {r}^{2}  \\  \\  \therefore \:  {r}^{2}  =  \frac{169\pi }{\pi}  \\  \\ \therefore \:  {r}^{2}  = 169 \\  \\ \therefore \:  {r} =  \pm \sqrt{169}  \\  \\\therefore \: r =  \pm \: 13 \: m \\ \\  \because \: radius \: of \: a \: circle \: can \: not \: be \: a \: negative \: \\quantity \\    \\  \huge \red{ \boxed{\therefore \: r =  13 \: m }}

5 0
3 years ago
Consider the absolute value equation x+2=3
Anna007 [38]
X would equal 1 in this problem since 1+2=3 and the absolute value(s) in this equation would be -1+(-2)=3 since, a negative plus a negative equals a positive.

I hope this helped you!
3 0
4 years ago
Suppose an isosceles triangle has two sides of length 42 and 35, and that the angle between these two sides is 120 degree. what
Citrus2011 [14]
Suppose that a=42, b=35, c is unknown, and C = 120°

c^2 = a^2 + b^2 -2ab(cosC)

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3 0
4 years ago
From a shipment of 400 light-bulbs, a sample of 80 was selected at random and tested. If 32 light-bulbs in the sample were found
denis-greek [22]
80 x 5 = 400
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4 0
3 years ago
A 13-foot ladder is leaning against a wall. If the top slips down the wall at a rate of 2 ft/s, how fast will the foot be moving
dimulka [17.4K]

Answer:

\frac{db}{dt}=\frac{20\sqrt{69}}{69}\approx2.4077\text{ ft/s}

Step-by-step explanation:

We know that the ladder is 13 feet long.

We also know that the top of the ladder is slipping down at a rate of 2ft/s.

And we want to find the rate at which the foot of the ladder is moving away when the top is 10 feet above the ground.

We can use the Pythagorean Theorem for this problem:

a^2+b^2=c^2

Let's let a be the leg by the wall, and b be the leg on the ground.

Our hypotenuse is 13 and it stays 13. So, let's substitute 13 for c:

a^2+b^2=(13)^2=169

Now, let's take the derivative of both sides with respect to t:

\frac{d}{dt}[a^2+b^2]=\frac{d}{dt}[169]

Evaluate. Use implicit differentiation:

2a\frac{da}{dt}+2b\frac{db}{dt}=0

We know that the top of the ladder is slipping down at a rate of 2ft/s. So, da/dt is -2 (it's negative because it's slipping <em>downwards</em>).

We want to find db/dt when the top is 10 feet above the ground. So, substitute 10 for a.

Since a is 10 and we know that c stays constant at 13, we can figure out b using the Pythagorean Theorem:

10^2+b^2=13^2

Evaluate:

100+b^2=169

Solve for b:

b^2=69\\b=\sqrt{69}

So, substitute -2 for da/dt, 10 for a, and √69 for db/dt. This yields:

2(10)(-2)+2(\sqrt{69})(\frac{db}{dt})=0

Solve for db/dt. Multiply:

-40+2(\sqrt{69})(\frac{db}{dt})=0

Add 40 to both sides:

2\sqrt{69}(\frac{db}{dt})=40

Divide both sides by 2√69:

\frac{db}{dt}=\frac{20}{\sqrt{69}}

Rationalize:

\frac{db}{dt}=\frac{20\sqrt{69}}{69}\approx2.4077\text{ ft/s}

So, the foot will be moving at approximately 2.4077 feet per second.

7 0
3 years ago
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