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geniusboy [140]
3 years ago
11

Michelle ran 2,051 meters at a constant speed over 7 minutes. What was Michelle's pace?

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

293 meters per minute

Step-by-step explanation:

perform 2051 divided by 7 to find the number of meters she ran per minute

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The following ratios are equivalent 16 girls to 12 boys and 8 girls : 6 boys
Cloud [144]

Answer:

Step-by-step explanation:

The ratio of boys to girls is 12 to 16, 12:16 or 12/16 (all different ways this can be written). The fraction form 12/16 can be reduced by dividing by the greatest common factor. Both 12 and 16 are divisible by 4, so the reduced fraction is 12/4 over 16/4 = 3/4. In other words, there are 3 boys for every 4 girls in the class.

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A gallon of paint will cover 144 square feet of floor space. What are the dimensions of the largest square floor that the gallon
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You want the largest SQUARE floor then both of the sides have to be the same. Since one gallon can cover up 144 square feet, to work out the dimensions you have to find the square root of 144 which is 12. So the largest square floor it can cover has dimensions 12x12 feet.
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3 years ago
7x2–5 - 28-3+5.
malfutka [58]

I can't read, sorry.

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I need help on this question please!!!
Hatshy [7]

Answer:

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Step-by-step explanation:

4 0
2 years ago
Una lancha que viaja a 10 m/s pasa por debajo de un puente 3 segundos después que ha pasado un bote que viaja a 7 m/s, ¿después
ExtremeBDS [4]

Answer:

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

Step-by-step explanation:

Sea el punto debajo del puente el punto de referencia y que ambas lanchas se desplazan a velocidad a continuación, las ecuaciones cinemáticas para cada embarcación son presentadas a continuación:

Bote a 7 metros por segundo

x_{A} = x_{o}+v_{A}\cdot t (Ec. 1)

Lancha a 10 metros por segundo

x_{B} = x_{o}+v_{B}\cdot (t-3\,s) (Ec. 2)

Donde:

x_{o} - Posición debajo del puente, medido en metros.

x_{A}, x_{B} - Posición final de cada embarcación, medido en metros.

v_{A}, v_{B} - Velocidad de cada embarcación, medida en metros por segundo.

t - Tiempo, medido en segundos.

Para determinar la posición en la que ambas embarcaciones se encuentran, se debe determinar el instante en que ocurre a partir de la siguiente condición: x_{A} = x_{B}

Igualando (Ec. 1) y (Ec. 2) se tiene que:

v_{A}\cdot t = v_{B}\cdot (t-3\,s)

Ahora despejamos el tiempo:

3\cdot v_{B} = (v_{B}-v_{A})\cdot t

t = \frac{3\cdot v_{B}}{v_{B}-v_{A}}

Si sabemos que v_{B} = 10\,\frac{m}{s} y v_{A} = 7\,\frac{m}{s}, entonces:

t = \frac{3\cdot \left(10\,\frac{m}{s} \right)}{10\,\frac{m}{s}-7\,\frac{m}{s}}

t = 10\,s

Ahora, la posición de encuentro es: (x_{o} = 0\,m, v_{A} = 7\,\frac{m}{s} y t = 10\,s)

x_{A} = 0\,m + \left(7\,\frac{m}{s} \right)\cdot (10\,s)

x_{A} = 70\,m

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

6 0
3 years ago
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