All categories

3 years ago

28 POINTS!!!!!! Solve for x. Please Help

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

7 0

The correct answer is the first option which is negative 2

svet-max [94.6K]3 years ago

6 0

Answer:

The third choice, $x\leq -8$

Step-by-step explanation:

One way to do it is to substitute in the potential answers. I'll show you here.

Choice 1

$2(-2)+3\leq (-2)-5$

$-4+3\leq -2-5$

$-1\leq -7$

We can see that this is false, so the answer cannot be choice 1.

Choice 2

$2(2)+3\leq (2)-5$

$4+3\leq 2- 5$

$7\leq -3$

This is also false, so the answer cannot be choice 2.

Choice 3

$2(- 8)+ 3\leq (-8)-5$

$-16+3\leq -8-5$

$-13\leq -13$

This is true. Let's see if choice 4 works.

Choice 4

$2(8)+3\leq (8)-5$

$16+3\leq 8-5$

$19\leq 3$

This is not true. Therefore, 3 is correct.

You might be interested in

A circle with radius of 9 cm sits inside a circle with radius of 11

saul85 [17]

Ok so to answer this, we first need to figure out the area of both circles
we will use the formula A=πr²

so our two areas end up being 121π and 81π

now all we do is subtract the smaller from the larger

121π - 81π = 40π

shaded region = 40π

8 0

3 years ago

In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer

stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = percentage of patients stop smoking when given sustained care.

So, Null Hypothesis, $H_0$ : p = 80% {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, $H_A$ : p $\neq$ 80% {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of patients who stop smoking when given sustained care = 80.2%

n = sample of patients = 192

So, the test statistics = $\frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }$

= 0.07

The value of z test statistics is 0.07.

Also, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.07) = 1 - P(Z $\leq$ 0.07)

= 1 - 0.52790 = 0.4721

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0

3 years ago

Use the equation to predict how many glasses with 9

cluponka [151]

Answer:

Bella can sell 13.78 glasses with 9 pieces of bling.

Step-by-step explanation:

Given the function

y=1.36x+1.54