The answer choice which represents the what is needed to construct a hexagon is Choice B; Six isosceles triangles.
What is needed to construct a hexagon?
By definition, an hexagon is a closed figure with six equal sides and six congruent interior angles.
On this note, upon assembly of six isosceles triangle s in which cases, the excluded side of the isosceles triangles form the sides of the hexagon and the congruent sides represents lines joining each vertex to the center of the hexagon, an hexagon is formed.
Read more on hexagon;
brainly.com/question/1615720
#SPJ1
7 = Tenth
7 is the first decimal of the number making it a tenth.
Answer:
A restaurant sells 10 tacos for $8.49, or 6 of the same kind of taco for $5.40. ... The 6 taco pack is a better deal. This is because the 10-pack has a unit rate of about $0.95 per taco, and the 6-pack has a unit rate of about $0.90 per taco.
<em>Hope this helps!</em>
Answer: B
Step-by-step explanation:
The equation 
is not yet in slope-intercept form(
). Simply subtract 2 from both sides to turn the equation into slope intercept form as 
. For a line to be perpendicular to another, it must have an opposite reciprocal slope. A reciprocal is the fraction reversed, where the numerator is the denominator and vice versa. Thus, 3/4 would become 4/3. The opposite reciprocal of 3/4 would be -4/3.
The slope of the line given is 3/4. Thus, simply plug in the opposite reciprocal of 3/4 for the slope to get: 
. Then, because the line passes through -12, 1, plug those values in for x and y, respectively.
Thus, the equation of the line is 
, or B.
Hope it helps :D
Answer:
<h2>(3, -2)</h2>
Step-by-step explanation:
Put the coordinates of the points to the inequality and check:
y < -1/2x + 2
for (2, 3) → x = 2, y = 3
3 < -1/2(2) + 2
3 < -1 + 2
3 < 1 FALSE
============================
for (2, 1) → x = 2, y = 1
1 < -1/2(2) + 2
1 < -1 + 2
1 < 1 FALSE
============================
for (3, -2) → x = 3, y = -2
-2 < -1/2(3) + 2
-2 < -1.5 + 2
-2 < 0.5 TRUE
============================
for (-1, 3) → x = -1, y = 3
3 < -1/2(-1) + 2
3 < 1/2 + 2
3 < 2 1/2 FALSE
