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3 years ago

Help asap pls i’ll give brainlist!

Mathematics

1 answer:

MrRa [10]3 years ago

3 0

Step-by-step explanation:

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What are the steps, in the correct order, to write and solve an equation?

kiruha [24]

Answer:

i would Identify the variable, Identify the operation, write an equation, solve the equation, check the solution.

Step-by-step explanation:

sorry if this is wrong.

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3 years ago

Is the square root of 42.25

liraira [26]

Answer: It’s 6.5

Step-by-step explanation: Bruh just look it up on google

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3 years ago

Please help me 16% of what is 41?

saul85 [17]

The answer is 256.25

EXPLANATION

Let $x$ represent the number.

Then, $\frac{16}{100}x=41$

We cross multiply yo obtain,

$16x=41\times 100$

We now divide both sides by 16.

$x=\frac{4100}{16}$

This will give us,

$x=256.25$

Therefore the number is 256.26

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3 years ago

Point L is on line segment KM. Given KM = 11 and KL = 5, determine the<br> length LM

NeTakaya

It’s -6/77 seconds because the line segment of km is given 11

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3 years ago

Can you tell me how to calculate R for below Matrix ?

scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

$x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}$

Reduce the matrix in row echelon form as shown:

$R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\$

$R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}$

$R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}$

$R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}$

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0

3 years ago