The probability of selecting a female student for the first picking is

The number of students left to select from after the first two students selected is 50 - 2 = 48 students, which consist of 34 females (two have been selected) and 14 males (none has been selected so far)

The probability that the third pick is a male is

the answer is b its like a mirror on opposite sides

1)

c=(107.5/100)(79.95+2(19.99))

c=1.075(79.95+39.98)

c=1.075(119.93)

c=128.92475

c≈$128.92 (to nearest cent)

2)

w=1700(10.5/100)

w=$178.50

3)

m=1700(1.25/100)

m=$21.25

4)

ss=1700(5.7/100)

ss=$96.90

5)

I=175(.035)*5+175(.035)*4+175(.035)3...

I=175(.035)(5+4+3+2+1)

I=175(.035)(15)

I≈$91.89 to nearest cent

6)

I=Pr^t-P

I=500(104.2/100)^7-500

I=500(1.042^7-1)

I≈$167.00 to nearest dollar

7)

A=(50+11*0.89)/11≈$5.44 per lb

B=(57+11*0.49)/11≈$5.67 per lb

C=(60-5)/11=$5.00 per lb

D=(58*(100-10)/100)/11≈$4.75 per lb

So D is the best deal at just $4.75 per lb.

**Answer:**

1/2 is the answer

**Step-by-step explanation:**

**Answer:**

A, C, E

**Step-by-step explanation:**

Substitute the x- coordinate of the points into the equation and if the result is equal to the y- coordinate of the point then it is a solution.

A (- 2, 5 )

y = 2² + 1 = 4 + 1 = 5 → (- 2, 5 ) is a solution

B (- 1, 0 )

y = (- 1)² + 1 = 1 + 1 = 2 ≠ 0 ← not a solution

C (1, 2 )

y = 1² + 1 = 1 + 1 = 2 → (1, 2 ) is a solution

D (2, 4 )

y = 2² + 1 = 4 + 1 = 5 ≠ 4 ← not a solution

E (3, 10 )

y = 3² + 1 = 9 + 1 = 10 → (3, 10 ) is a solution