The probability of selecting a female student for the first picking is

The number of students left to select from after the first two students selected is 50 - 2 = 48 students, which consist of 34 females (two have been selected) and 14 males (none has been selected so far)
The probability that the third pick is a male is
the answer is b its like a mirror on opposite sides
1)
c=(107.5/100)(79.95+2(19.99))
c=1.075(79.95+39.98)
c=1.075(119.93)
c=128.92475
c≈$128.92 (to nearest cent)
2)
w=1700(10.5/100)
w=$178.50
3)
m=1700(1.25/100)
m=$21.25
4)
ss=1700(5.7/100)
ss=$96.90
5)
I=175(.035)*5+175(.035)*4+175(.035)3...
I=175(.035)(5+4+3+2+1)
I=175(.035)(15)
I≈$91.89 to nearest cent
6)
I=Pr^t-P
I=500(104.2/100)^7-500
I=500(1.042^7-1)
I≈$167.00 to nearest dollar
7)
A=(50+11*0.89)/11≈$5.44 per lb
B=(57+11*0.49)/11≈$5.67 per lb
C=(60-5)/11=$5.00 per lb
D=(58*(100-10)/100)/11≈$4.75 per lb
So D is the best deal at just $4.75 per lb.
Answer:
1/2 is the answer
Step-by-step explanation:
Answer:
A, C, E
Step-by-step explanation:
Substitute the x- coordinate of the points into the equation and if the result is equal to the y- coordinate of the point then it is a solution.
A (- 2, 5 )
y = 2² + 1 = 4 + 1 = 5 → (- 2, 5 ) is a solution
B (- 1, 0 )
y = (- 1)² + 1 = 1 + 1 = 2 ≠ 0 ← not a solution
C (1, 2 )
y = 1² + 1 = 1 + 1 = 2 → (1, 2 ) is a solution
D (2, 4 )
y = 2² + 1 = 4 + 1 = 5 ≠ 4 ← not a solution
E (3, 10 )
y = 3² + 1 = 9 + 1 = 10 → (3, 10 ) is a solution