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inn [45]
3 years ago
13

what is the equation for the line that passes through the given point and is parallel to the graph of y=2/3x+19; (-9, 4)​

Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

Step-by-step explanation:

We're given the line

y = \frac{2}{3}(x) + 19

The slope of the line is \frac{2}{3}

We have to find another line with the same slope that goes through the point

(-9, 4). We can solve this by using

y = mx + b\\y = \frac{2}{3}(x) + b\\4 = \frac{2(-9)}{3} + b\\4 = -6+ b\\b = 10\\\\y = \frac{2}{3}(x) + 10

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Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
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Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

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(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

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