Question

what is the equation for the line that passes through the given point and is parallel to the graph of y=2/3x+19; (-9, 4)​

Answer 1

Answer:

Step-by-step explanation:

We're given the line

$y = \frac{2}{3}(x) + 19$

The slope of the line is $\frac{2}{3}$

We have to find another line with the same slope that goes through the point

$(-9, 4)$. We can solve this by using

$y = mx + b\\y = \frac{2}{3}(x) + b\\4 = \frac{2(-9)}{3} + b\\4 = -6+ b\\b = 10\\\\y = \frac{2}{3}(x) + 10$