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Step2247 [10]
3 years ago
7

Click on the correct answer.

Mathematics
2 answers:
natali 33 [55]3 years ago
7 0
It’s d because 90% of 120 is 1.08 so you add the 1.08 to the 1.20 and you get 2.28 trust me it’s correct
Galina-37 [17]3 years ago
5 0

Answer:

A, $1.08

Step-by-step explanation:

1.20 / 90 = 1.08

use a calculator

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1. The graph of y = x2 is translated 4 units down and 3 units to the left. It is also stretched by a factor
slega [8]

Answer:

ok so first ur gonna do 4x3=12 then

Step-by-step explanation:

7 0
2 years ago
What is the equation when y=5x+4 is reflected over the x-axis, y-axis & y=x?
tigry1 [53]

Answer:

A) y=-5x-4

B) y=-5x+4

C) y=\frac{x-4}{5}

Step-by-step explanation:

So we have the equation:

y=5x+4

Let's write this in function notation. Thus:

y=f(x)=5x+4

A)

To flip a function over the x-axis, multiply the function by -1. Thus:

f(x)=5x+4\\-(f(x))=-(5x+4)

Simplify:

-f(x)=-5x-4

B) To flip a function over the y-axis, change the variable x to -x. Thus:

f(x)=5x+4\\f(-x)=5(-x)+4

Simplify:

f(-x)=-5x+4

C) A reflection over the line y=x is synonymous with finding the inverse of the function.

To find the inverse, switch x and f(x) and solve for f(x):

f(x)=5x+4

Switch:

x=5f^{-1}(x)+4

Subtract 4 from both sides:

x-4=5f^{-1}(x)

Divide both sides by 5:

f^{-1}(x)=\frac{x-4}{5}

And we're done :)

7 0
3 years ago
Determine the value of 217
BlackZzzverrR [31]
The answer in decimal form should be 5.3 if you round it up
4 0
3 years ago
What is 3/4 of 16/21? worked out please
timofeeve [1]
Of means multiplication

So

\frac{3}{4} \sf{of}  \frac{16}{21}  =  \frac{3}{4} \times  \frac{16}{21}

And then simplify the numerator ad denominator

= \frac{3 \times 16}{4 \times 21} =  \frac{\ 1 \times 16}{4 \times 7}

And simplify the numerator and denominator again

= \frac{\ 1 \times 16}{4 \times 7} = \frac{\ 1 \times 4}{1 \times 7}

And we are finally left with the answer which is \frac{4}{7}
5 0
3 years ago
Solve inequality √(2−x) < x.
Bond [772]
[tex]\sqrt{2-x}0\\ x^2+2x-x-2>0\\ x(x+2)-1(x+2)>0\\ (x-1)(x+2)>0\\ x\in(-\infty,-2)\cup(1,\infty)\\\\ \boxed{x\in(-\infty,-2)\cup(1,2\rangle}[/tex]
5 0
3 years ago
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