Answer:
Research Hypothesis solves the problem by .....
Step-by-step explanation:
Research Hypothesis is a set of assumed statements, consisting certain variables & their relationships
The variables whose relationship are to be checked by hypothesis testing, are independent & dependent variables. The causal variable(s) are independent variables & the effected variable is the dependent variable.
- Null Hypothesis : It is the hypothesis assuming no statistically significant relationship between independent & dependent variables
- Alternate Hypothesis : It is the hypothesis assuming statistically significant relationship between independent & dependent variable
Example : To check the research question, of relationship between research variables, by formulating hypothesis assumed statement
Y = b0 + b1X ; where
Y = dependent variable, X = independent variable, b0 = autonomous, b1 = X intercept on Y
- H0 : b1 = 0 {No significant relationship between X & Y}
- H1 : b1 ≠ 0 {Significant relationship between X & Y}
This way : Research hypothesis solves the problem by - formulating hypothesis assumptions, which recognise the variables & their relations. At last, acceptance of null or alternate hypothesis gives the final research conclusion & interpretation
Answer:
30.31%
Step-by-step explanation:
Mark up on selling price is given by markup*100%/selling price
In this case, markup is given as $870 while the selling price is $2870 hence the percentage of narkup to selling price will be given by 
Therefore, the percentage of markup to selling price is approximately 30.31%
Answer:
7.8
Step-by-step explanation:
Simplifying
2x + 3y = 12
Solving
2x + 3y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3y' to each side of the equation.
2x + 3y + -3y = 12 + -3y
Combine like terms: 3y + -3y = 0
2x + 0 = 12 + -3y
2x = 12 + -3y
Divide each side by '2'.
x = 6 + -1.5y
Simplifying
x = 6 + -1.5y
Answer:
Step-by-step explanation:
\frac{4}{3x²-23x+40}
=\frac{4}{3x²-15x-8x+40}
=\frac{4}{3x(x-5)-8(x-5)}
=\frac{4}{(x-5)(3x-8)}
=\frac{4(x-3)}{(x-5)(3x-8)(x-3)}
2.
\frac{9x}{3x²-17x+24}
=\frac{9x}{3x²-9x-8x+24}
=\frac{9x}{3x(x-3)-8(x-3)}
=\frac{9x}{(x-3)(3x-8)}
=\frac{9x(x-5)}{(3x-8)(x-5)(x-3)}
