4.3496 miles.
HTH (Hope This Helps)
Answer:
The function represents a direct variation
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form
or 
In a linear direct variation the line passes through the origin and the constant of proportionality k is equal to the slope m
Let
------> the line passes through the origin

Find the value of k------> substitute the value of x and y
-----> 

Find the value of k------> substitute the value of x and y
-----> 

Find the value of k------> substitute the value of x and y
-----> 

Find the value of k------> substitute the value of x and y
-----> 
The value of k is equal in all the points of the table and the line passes through the origin
therefore
The function represents a direct variation
the equation of the direct variation is equal to

<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
20? I’m not for sure maybe look in the book? That’s the answer I got and it was right