Find the equation of the line that contains the point (-1,-11) and is parallel to the line 7x+3y=10
1 answer:
Y=- \frac{7}{3} 
.
To find the equation of a line, you need two things: the slope and the y-intercept.
The slopes of parallel lines are the same. So we can find the slope of the new line by finding the slope of the first line. To do that, we need to put it in y=mx+b format, where m is the slope. So we must rearrange the 7x+3y=10. First subtract 7x from both sides to make it look like:
Then divide both sides three:
b
So now that it's in y=mx+b format, we can now see that the m= - \frac{7}{3}
Now we know the m of the new equation, we need to find the b, or the y-intercept. To do this, we can plug the point we have and the m value into the y=mx+b format.
Solving this, we can subtract 7/3 from both sides:
Therefore, b=
Plugging the m= - \frac{7}{3} and the b= back into the y=mx+b format, your parallel line is y=- \frac{7}{3} .
To find the equation of a line, you need two things: the slope and the y-intercept.
The slopes of parallel lines are the same. So we can find the slope of the new line by finding the slope of the first line. To do that, we need to put it in y=mx+b format, where m is the slope. So we must rearrange the 7x+3y=10. First subtract 7x from both sides to make it look like:
Then divide both sides three:
b
So now that it's in y=mx+b format, we can now see that the m= - \frac{7}{3}
Now we know the m of the new equation, we need to find the b, or the y-intercept. To do this, we can plug the point we have and the m value into the y=mx+b format.
Solving this, we can subtract 7/3 from both sides:
Therefore, b=
Plugging the m= - \frac{7}{3} and the b=
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Answer:
(1,4)
Step-by-step explanation:
Let's this of which is it's parent function.
How do we get to from there?
It has been reflected about the a-axis because of the - in front of the square root.
It has been shifted right 1 unit because of the -(1) in the square root.
It has been moved up 4 units because of the +4 outside the square root.
In general:
has the following transformations from the parent:
Moved right h units if h is positive.
Moved left h units if h is negative.
Moved up k units if k is positive.
Moved down k units if k is negative.
If is positive, it has not been reflected.
If is negative, it has been reflected about the x-axis.
also tells us about the stretching factor.
The parent function has a starting point at (0,0). Where does this point move on the new graph?
It new graphed was the parent function but reflected over x-axis and shifted right 1 unit and moved up 4 units.
So the new starting point is (0+1,0+4)=(1,4).