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riadik2000 [5.3K]

3 years ago

12

Line A (y = 3x – 3) is transformed into

1 answer:

arsen [322]3 years ago

6 0

Steeper and the line shifted +4 up (Talking about the y intercept)

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The mean temperature for the first 7 days in January was 6 °C.

hodyreva [135]

Hope this help!!!

Have a nice day!!!

4 0

2 years ago

In the equation y = kx, what does the variable k represent?

anyanavicka [17]

Answer:

I think it B but I really don't know cause need like an example

8 0

2 years ago

Which set of shapes could be used to form a net for a square pyramid?

bulgar [2K]

Answer:

A.1 square and 4 triangles

Step-by-step explanation:

A pyramid has sides that are triangular faces and a base. In a square pyramid, the base is a square.

The net therefore has 1 Square and 4 Triangles.

A net is given in the attached diagram:

8 0

3 years ago

What is the exact time t, in years, needed for the balance of an account that earns 5% annual 8. Interest compounded continuousl

Brums [2.3K]

Answer:

It takes 22.52 years for the balance to triple in value.

Step-by-step explanation:

Continuous compounding:

The amount of money earned using continuous compounding is given by the following equation:

$A(t) = A(0)(1+r)^t$

In which A(0) is the initial amount of money and r is the interest rate, as a decimal.

Interest rate of 5%.

This means that $r = 0.05$ , and thus:

$A(t) = A(0)(1+r)^t$

$A(t) = A(0)(1+0.05)^t$

$A(t) = A(0)(1.05)^t$

Time for the balance to triple?

This is t for which $A(t) = 3A(0)$ . So

$A(t) = A(0)(1.05)^t$

$3A(0) = A(0)(1.05)^t$

$(1.05)^t = 3$

$\log{(1.05)^t} = \log{3}$

$t\log{1.05} = \log{3}$

$t = \frac{\log{3}}{\log{1.05}}$

$t = 22.52$

It takes 22.52 years for the balance to triple in value.

3 0

3 years ago

You are riding a roller coaster when a shoe falls off your foot. The function y=300−16t2 represents the height y (in feet) of th

Juli2301 [7.4K]

Answer:

Time to land on 11ft is 4.25 seconds

Step-by-step explanation:

Given

$y = 300 - 16t^2$

Required

Solve for t when height is 11ft

This implies that $y = 11$

So: substitute 11 for y in $y = 300 - 16t^2$

$11 = 300 - 16t^2$

Collect Like Terms

$16t^2 = 300 - 11$

$16t^2 = 289$

Express both sides as squares

$4^2 * t^2 = 17^2$

$(4t)^2 = 17^2$

Take square roots of both sides (ignore negative)

$4t = 17$

Solve for t

$t = \frac{17}{4}$

$t = 4.25$

Hence, time to land on 11ft is 4.25 seconds

8 0

2 years ago