Answer:
For t=3 sec the velocity change from positive to negative
Step-by-step explanation:
we have

This is the equation of a vertical parabola open downward (the leading coefficient is negative)
where
s(t) is the distance in feet
t is the time in seconds
We know that
To find out when the velocity change from positive to negative, we need to determine the turning point of the quadratic equation
The turning point of the quadratic equation is the vertex
so
Convert the quadratic equation into vertex form

Factor -16

Complete the square


Rewrite as perfect squares

The vertex is the point (3,244)
therefore
For t=3 sec the velocity change from positive to negative
The ratio would look like 63:3.5, if simplified it would look like 18:1
Answer:
(f.g)(x)=4x^3+4x^2
Step-by-step explanation:
f(x) = 4x^2and g(x) = x+1, (f•g)(x)=?
(f.g)(x)=f(x)*g(x)
(f.g)(x)=4x^2*(x+1)
(f.g)(x)=4x^3+4x^2
hope it helps. .brainliest please
Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.