The standard form for an equation is y=mx+b. You find the slope by using the formula of rise over run. This means that for problem 6 you first look to see if its positive or negative slope. The slope is positive if the line is going uphill and if its going downhill its negative. The slope would be negative for number 6 because it is going downhill. Then for the actualy slope you would start with rise. So you look at the point (0,1) and go up 3 until you hit the line of the other point and run over 2. So your slope would be -3/2.
Use the Pythagorean theorem
Side = sqrt(8^2 - 6^2)
Side = sqrt(64-36)
Side = sqrt(28)
Side = 5.29
Rounded to nearest tenth = 5.3
Answer:
the 4th one
Step-by-step explanation:
Answer:
gev5y
Step-by-step explanation:
Answer:
The object will hit the ground after 10.308 seconds.
Step-by-step explanation:
h(t) = -16t² + 1700
If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.
-16t² + 1700 = 0 Plug this into a calculator if you have one.
t = -10.308 and t = 10.308
Since time can't be negative, your answer will be the positive value, 10.308.
