<span>Fine the difference between the proud of 26.22 and 3.09 and the sum of 3.507,208,11.5,and 16.712.:
</span>
60.800591885
Answer:
At 6 p.m., the number of cars in a parking lot is 120
Step-by-step explanation:
At 1 p.m., the number of cars in a parking lot is 78.
Given,
Note that
So, 1 p.m. goes for n = 0, then
6 p.m. goes for n = 5
Thus,
Answer:
80
Step-by-step explanation:
Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
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