2 years ago

Classify each polynomial based on the number of terms it contains.

Mathematics

1 answer:

pantera1 [17]2 years ago

8 0

Answer:

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Step-by-step explanation:

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Marina86 [1]

Answer:

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Step-by-step explanation:

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2 years ago

the graph of a linear function is given below. What is the zero of the function? a) -5. b) 2/5. c) 2. d) 5/2

Murrr4er [49]

The zero of a function is the x-value at which the function value is zero. That is, the value of the function that intersects the x-axis. From the picture, the zero is -5

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1 year ago

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Greeley [361]

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Step-by-step explanation:

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2 years ago

11 + 2(z + 3) -z simplified

lbvjy [14]

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Step-by-step explanation:

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2 years ago

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Find an exact value cos(19pi/12)

dmitriy555 [2]

$cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

Step-by-step explanation:

We know that

cos 2x = 2cos²x - 1

So we have

$cosx=\sqrt{\frac{1+cos2x}{2}}$

Substituting $x=\frac{19\pi}{12}$

$cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos2\left ( \frac{19\pi}{12}\right )}{2}}\\\\cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos\left ( \frac{19\pi}{6}\right )}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1+cos570}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{2-\sqrt{3}}{4}}\\\\cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

$cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

3 0

2 years ago

Read 2 more answers