The line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9
<h3>Parallel Equations</h3>
The given equation is:
y = 4x + 5
Compare y = 4x + 5 with the equation y = mx + c
m = 4, c = 5
The equation parallel to y = 4x + 5 will also have a slope, m = 4
The point-slope form of the equation of a line is given as:
y - y₁ = m(x - x₁)
substitute m = 4, x₁ = -2 and y = 1 into the equation above
y - 1 = 4(x - (-2)
y - 1 = 4(x + 2)
y - 1 = 4x + 8
y = 4x + 8 + 1
y = 4x + 9
Therefore the line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9
Learn more on equation of a line here: brainly.com/question/13763238
To find the x-intercept, set y=0 and solve for x.
To find the y-intercept, set x=0 and solve for y.
7x+6y=21
x-int: y=0
7x+6(0)=21
7x=21
x=3
y-int: x=0
7(0)+6y=21
6y=21
y=21/6 or 7/2
Answer: 16y² - x²
Step-by-step explanation: The - sign means a difference, so the choices with + signs are eliminated (though 64x² and 9 are squares)
10 is not a square so that one is eliminated (though the y² and the 4x² are squares)
16 is the square of 4, y² is the square of y, and x² is the square. That expression shows a difference of squares.
I must assume that your graph is that of a straight line, and that the end points of the line are P and B, and (finally) that T is between P and B. If these assumptions are correct, then the length of the line segment PB connecting points P and B is 15 + 10, or 25.
