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Leno4ka [110]
4 years ago
5

Deaths of Mt. Everest climbers were first recorded in 1921. From that time through March 21, 2013, there have been 240 deaths. T

he total number of deaths from falling is 65. This number is 13 more than twice the number who died of exposure/ frostbite. How many climbers died of exposure/ frostbite?
Mathematics
1 answer:
Ymorist [56]4 years ago
7 0
The total of climbers that died of exposure/frostbite is 175 climbers
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Разстоянието между селищата A и B е 410 км.От A за B пътува лека кола със скорост 90km/h, а 1 h по-късно от B за A тръгва камион
harkovskaia [24]

4,56 км / ч просто разделят ускорението и точката на среща.

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3 years ago
The perimeter of an isosceles triangle is p = 2a + b. Find the numerical value of a if p = 10 and b = 3.
bagirrra123 [75]
P = 2a + b
10= 2a + 3
2a = 10-3
a = 7/2 = 3.5


Therefore, numerical value of a is 3.5
7 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
I need so much help !!!!!!!!!!!<br> !!
lbvjy [14]
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3 years ago
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Suppose you are driving 60 miles per hour. what is your rate of speed in miles per minute?
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So if it is 60 miles per hour it is basically 60 miles per 60 minutes. \frac{60}{60} when you simplify it, it is going to be 1/1=1 The answer is 1 mile per minute

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3 years ago
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