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Tanzania [10]
2 years ago
12

A rectangular field is to be enclosed by a fence and divided

Mathematics
1 answer:
Phantasy [73]2 years ago
5 0

Answer:

80000 square meters

Step-by-step explanation:

perimeter + dividing fence = 800

let a = length

let b = width

let c = length of dividing fence

perimeter = 2*a + 2*b

let's say...

c is the same as the length

2a + 2b + c = 800

2a + 2b + a = 800

3a + 2b = 800

area = length*width

area = a*b

area / b = a

3*(area/b) + 2b = 800

3*(area/b) = 800 - 2b

area/b = (800 - 2b)

area = (800 - 2b)*b

To make the area large, we make the right hand side large.

800b - 2b^2

If you put in terms of x, y it looks like a downward opening parabola, so the max area is at the vertex. Half way between the roots.

y = -2x^2 + 800x

y = -x^2 + 400x

0 = x*(-x + 400)

roots are x= 0 and x = 400

vertex is at x, aka b = 200

area at b=200 is (800 - 400)*200 = 80000

and a is area/b... 80000/400 = 200

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Answer:

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Step-by-step explanation:

First you write the equation 2(2x-4)=28 because if b is the midpoint then AB is half of the line so you multiply that half by two the make it equal to the whole line.

Then you distribute the two and get 4x-8=28.

Then you add 8 to 28 and get 36.

Then you divide 36 by 4 because the 4 and x are being multiplied together so you have to divide to get them apart.

So then you get x=9 and you aren't done yet because you have to plug x into 2x-4.

So it is 2(9)-4 which is 18-4 which equals 14.

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Step-by-step explanation:

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Step-by-step explanation:

To solve this question, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

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