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saul85 [17]
3 years ago
7

conducted an experiment with orange, purple and blue colored lights to grow spinach. During their experiment, they conducted a c

hi-square analysis. Their chi-square sum was 0.85. If their sum is less than the probability value, then their data fits their experiment to reject the null. If their sum is greater than the probability value to, then their data does not fit their experiment to accept the null. What was the conclusion of the data results for their experiment
Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

There is not enough evidence to reject the null hypothesis.

Their sum is greater than the probability value ,  the data does not fit the experiment and the null is  accepted.

Step-by-step explanation:

There are 3 colors so degrees of freedom = 3-1 = 2

The chi square value = 0.85

The p value for chi square =0.85 for 2 degrees of freedom for the left tailed test to be 0.34623 for 0.1,0.05 and 0.01 significance level.

There is not enough evidence to reject the null hypothesis.

The  p value for chi square =0.85 for 2 degrees of freedom for the right tailed test to be 0.65377 for 0.1,0.05 and 0.01 significance level.

There is not enough evidence to reject the null hypothesis.

Their sum is greater than the probability value ,  the data does not fit the experiment and the null is  accepted.

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If the area of a circle is 154m2 what is the circumference.
Sergeu [11.5K]

The radius is found from

... A = πr²

... r = √(A/π) = √(154/π) m ≈ 7.00 m

The circumference is then

... C = 2πr = 2π(7.00 m) ≈ 43.99 m

The circumference is about 44.0 m.

6 0
3 years ago
A water balloon is thrown out of a window 96 feet above the ground. The balloon is traveling downward at 16 feet per second init
Marysya12 [62]

Answer:

3 seconds.

Step-by-step explanation:

Since we are figuring out when the water balloon will hit the ground, y will need to be equal to 0.

0 = - 16t² - 16t + 96

Now we simply factor the trinomial to find t.

0 = -16(t² - t - 6)

0 = (t - 3)(t + 2)

t - 3 = 0 ⇒ t = 3

t + 2 = 0 ⇒ t = -2

Since we are referring to time, we need to use the positive value. Therefore, the water balloon will take 3 seconds to hit the ground.

6 0
3 years ago
Read 2 more answers
PLS HELP!
wolverine [178]

Given:

Alexis has a rectangular backyard that is 50 yards by 55 yards.

She wants to build a fence that stretches diagonally from one corner to the opposite corner.

To find:

The length of the fencing she needs.

Solution:

We have,

Length = 50 yards

Width = 55 yards

We know that, the diagonal of a rectangle is

Diagonal=\sqrt{length^2+width^2}

Diagonal=\sqrt{(50)^2+(55)^2}

Diagonal=\sqrt{2500+3025}

Diagonal=\sqrt{5525
}

On further simplification, we get

Diagonal=74.3303437

Diagonal\approx 74.3

Therefore, the length of the required fencing is 74.3 yards.

8 0
3 years ago
The speed of the current is 7 mph. The boat travels three times slower against the current than with the current. What is the sp
svlad2 [7]
Let
x--------> <span>the speed of the boat in mph

we know that
</span>going upstream the speed is x-7 
<span>going downstream the speed is x+7 
</span>
let the distance be d 
<span>time to go upstream = d/(x-7) </span>
<span>time to go downstream = d/(x+7)
</span>
time going upstream is 3 times going downstream 
so
<span>3d/(x+7) = d/(x-7) </span>
<span>divide by d </span>
<span>3/(x+7) = 1/(x-7) </span>
<span>3x-21 = x+7 </span>
<span>2x = 28 </span>
<span>x = 14 
</span>
the answer is
<span>the speed of the boat in still water is 14 mph</span>
7 0
3 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
3 years ago
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