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3 years ago

ASAP Find the slope of The ordered pairs (0,-17),(2,13)

Mathematics

2 answers:

bezimeni [28]3 years ago

4 0

Answer:

m=15

Step-by-step explanation:

kramer3 years ago

4 0

Answer:

1 5

Step-by-step explanation:

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Write a word phrase for each algebraic expression

Alex73 [517]

Y/5.....the quotient of y and 5

14.1 - w....the difference of 14.1 and w

9n + 1....the product of 9 and a number (n), increased by 1

(z/8) - 9.....9 less then the quotient of z and 8

15 - (1.5/d) ....15 decreased by the quotient of 1.5 and a number (d)

3 0

3 years ago

Beethoven wrote 9 symphonies, Mozart wrote 27 piano concertos, and Schubert wrote 15 string quartets. (i) If a university radio

Oduvanchick [21]

Answer:

This can be done in 3645 ways

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this problem, we have that:

1 Beethoven symphony, from a set of 9.

1 Mozart concerto, from a set of 27.

1 string quartets, from a set of 15.

$P_{(9,1)}*P_{(27,1)}*P_{(15,1)} = \frac{9!}{(9-1)!}*\frac{27!}{(27-1)!}*\frac{15!}{(15-1)!} = 3645$

This can be done in 3645 ways

4 0

3 years ago

Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?

oee [108]

The answer is $\frac{x^{4/3}y^{3}}{3}$ .

The fraction is: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }$
Let's rewrite it: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }$

Since $\frac{x^{a} }{x^{b}} =x^{a-b}$ ,
then:
*** $\frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}$
*** $\frac{y^{-2} }{ y^{-5} }= y^{-2-(-5)} = y^{-2+5} = y^{3}$
______
$\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}$

8 0

3 years ago

Ill marbrainlist plss help

Tju [1.3M]

It’s A!!!! 3:2 hope i helped

3 0

3 years ago

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If 400 g of chocolate sells for $12,<br> "how much is the cost per kilogram?

Kryger [21]

the cost of the chocolate of 1 kg will be 30$

4 0

3 years ago