For a half- life, the formula is
A(t) = A0(0.5)^( t / t_0.5)
where A(t) is the amount of substance at time t
A0 is the initial amount of subtance
t_0.5 is the time it will reduce its amount to half
t is the time
substitute the given to the formula
A(t) = 100(0.5)^( t/6 )
so the decay factor is 0.5^( t/6 )
Given
A survey found that 12 out of 30 people preferred bacon over sausage.
Find out the what percent of people prefer bacon over sausage.
To proof
As given in the question
survey found that 12 out of 30 people preferred bacon over sausage.
Total number of people = 30
people preferred bacon over sausage = 12
Formula
put the value in the formula

solve the above
percent of people prefer bacon over sausage = 40 %
Hence proved
Without so much as a quick peek at the picture, it's not possible to even begin
to answer the question. That's the reason, you see, that the picture is printed
right there, along with the question, in the same place from which you copied
this cut-off portion of the question. It's not enough. We need the picture too.