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3 years ago

8

A pair of equations is shown below.

2 answers:

olya-2409 [2.1K]3 years ago

8 0

A because if you do the math right you get a

PtichkaEL [24]3 years ago

6 0

Answer:

a

Step-by-step explanation:

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a box of energy bars contains 8 bars. the total weight of the bars is 10 2/3 ounces. if each bar has the same weight, what is th

maw [93]

The answer is 1 1/3 ounces. Divide 10 2/3 by 8 or multiply 32/3 by 1/8 which = 4/3 or 1 1/3 ounces.

7 0

3 years ago

The domain of u(x) is the set of all real values except 0 and the domain of v(x) is the set of all real values except 2. What ar

muminat

Answer:

Third option

x ≠2 and x cannot be any value for which v(x) = 0

Step-by-step explanation:

In this problem we are asked to find the domain of the function

$(UoV)(x)$

We know that $(UoV)(x) = U(V(x))$ .

We know that:

Domain of U(x) is all real numbers except <em>x = 0</em>

Domain of V(x) is all real numbers except <em>x = 2</em>.

Then the domain of the composite function U(V (x)) is:

all real numbers except <em>x = 2</em>. (since <em>x = 2</em> does not belong to the domain of V(x) and all values of x for which <em>V(x) = 0</em> (since <em>x = 0</em> does not belong to the domain of U(x))

Finally the domain of $(UoV)(x)$ ) is:

$x \neq 2$ and $V(x) \neq 0$

4 0

3 years ago

Read 2 more answers

Isaiah has $145 in his savings account. He earns $36 a week mowing lawns.

valentina_108 [34]

Answer:

8 weeks

Step-by-step explanation:

Amount saved from mowing lawns = $433 - $145

= $288

Number of weeks to save $288 from $36 a week = 288/36 = 8 weeks

3 0

3 years ago

What is greater 30% or 0.03

Orlov [11]

30 percent is greater because o0.03 is actually 3 Percent

5 0

3 years ago

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Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

3 years ago

Read 2 more answers