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marysya [2.9K]
3 years ago
7

Help! Please show work and identify the solution or how many solutions there are to the system

Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

Step-by-step explanation:

the two given lines are parallel.

Hence they do not intersect.

or they have no solution.

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Which graph shows the solution to the system of linear inequalities?
tangare [24]

Answer:

  • See below

Step-by-step explanation:

<u>Given system:</u>

  • y ≥ 2x + 1
  • y ≤ 2x – 2

The solution is the common area shaded by the inequalities.

The lines are parallel because of same slope.

Both lines are solid because of equal sign in both inequalities.

The first inequality has a y-intercept of 1 and shaded area is to the left of the line since the value of y is greater as x increases.

The second inequality has a y-intercept of -2 and shaded area is to the right of the line since the value of y is greater as x increases.

The matching graph is the second picture (or attached below) and there is no solution.

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Suppose x, y, and z are all rational numbers. Is
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Determine whether the point (1, 5) is a solution to the system of equations. Explain your reasoning in complete sentences.
Ivanshal [37]
The solution to any system graphically can be found where the 2 graphs intersect.  These two graphs intersect at the point (0, 2). 
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Jenny is having a party. She has one
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2 .............:)
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Plssssss help fast!!!!Launching From a Tower
aleksandrvk [35]

Answer:

A. h = 64

B.  t = 4 -> 4 seconds

C. t = 1.5 -> 1.5 seconds

D. maximum height is 100 ft

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

Step-by-step explanation:

h = -16t2 + vt + 64

A. What tower platform height was the projectile launched from?

when the projectile was not launched, t = 0

h = -16(0)^2 + v(0) + 64 = 64

B. How long was the projectile in the air?

if the projectile lands, its height = 0 so substitute 0 for h

0 = -16(t)^2 + 48(t) + 64

  = -16(t^2 - 3t -  4)

 = -16(t - 4)(t + 1)

t = 4 or t = -1

Since time can not be negative, t = -1 can not be the answer. Therefore, the projectile lands when t = 4 or 4 seconds.

C. When did it reach its maximum height?

maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16

t = -48/-32 = 1.5

D. What was its maximum height?

plug t = 1.5 into -16(t)^2 + 48(t) + 64

-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

6 0
2 years ago
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