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Crazy boy [7]
3 years ago
9

La frase lingüística "cuatro veces un número dividido por la suma de dos

Mathematics
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

Las opciones no se pueden ver, así que responderé de una forma general.

Primero rompamos la frase en partes más cortas

"cuatro veces un número..."

Esto se escribe como 4*N, donde N es el número.

"... la suma de dos

números"

Esto se escribe como K + M

donde K y M son dos números, entonces K + M es la suma de dos números.

Entonces:

"cuatro veces un número dividido por la suma de dos

números"

Se escribirá como:

(4*N)/(K + M )

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Why do you switch the inequality sign when multiplying or dividing by a negative?
Andreas93 [3]
If we multiply or divide both sides of an inequality by a negative number, you have to flip the inequality. Hope this helps :)
5 0
3 years ago
In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flower
lutik1710 [3]

<u>Question Completion</u>

(a)What is your null hypothesis?

(b)What is your expected phenotypic ratio based on Mendelian inheritance?

(c)Calculate the expected number of flowers you should have gotten based on the Mendelian inheritance. Then calculate a chi-square value, degrees of freedom, and a p-value.

  • Chi-square statistic: _____
  • Degrees of freedom (# phenotypes -1):
  • P-value:

(d)Interpret your results. Do you reject it or fail to reject your null hypothesis (please restate the null)?

Answer:

(a)H_0:$The given data fit the predicted phenotype

(b)9:3:3:1

(c)

  • Chi-square statistic: 3.8914
  • Degrees of freedom (# phenotypes -1) =3
  • P-value:  0.2734

(d)We fail to reject the null hypothesis.

Step-by-step explanation:

In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flowers (e). An F2 generation was created by crossing two F1 individuals (each BbEe).

(a)The null hypothesis is:

H_0:$The given data fit the predicted phenotype

(b)The gametes are BE, Be, bE and be.

The offsprings are presented in the table below:

\left|\begin{array}{c|cccc}&BE&Be&bE&be\\--&--&--&--&--\\BE&BE&BE&BE&BE\\Be&BE&Be&BE&Be\\bE&BE&BE&bE&bE\\be&BE&Be&bE&be\end{array}\right|

The expected phenotypic ratio based on Mendelian inheritance

BE:Be:bE:be=9:3:3:1

(c)

\left|\begin{array}{c|c|c|c|c|c}$Phenotype&Observed&$Expected&O-E&(O-E)^2&\dfrac{(O-E)^2}{E} \\-----&--&--&--&--&--\\$White short(BE)&206&\frac{9}{16}*404 \approx 227 &-21&441&1.9427\\$Red, short(bE)&83&\frac{3}{16}*404 \approx 78 &5&25&0.3205\\$White, tall(Be)&85&\frac{3}{16}*404 \approx 78 &7&49&0.6282\\$Red, tall(be)&30&\frac{1}{16}*404 \approx 25 &5&25&1\\-----&--&--&--&--&--\\$Total&404&--&--&--&3.8914\end{array}\right|

Therefore:

  • Chi-square statistic: 3.8914
  • Degrees of freedom (# phenotypes -1):  4-1 =3
  • P-value:  0.2734

(d) Our null hypothesis is:

H_0:$The given data fit the predicted phenotype

Since p>0.05, the given data fit the predicted phenotypic ratio.

We, therefore, fail to reject the null hypothesis.

The difference in the observed and expected are sosmall that they can be attributed to random chance.

8 0
3 years ago
HELP ME ASAP PLEASE!!
Daniel [21]

Answer:

set both of them equal to each other:

8x - 8° = 5x + 25°

subtract 5x by both sides of the equations and it becomes:

3x-8° = 25°

now add 8° both sides:

3x = 33°

divide three by both sides:

x = 11°

now thats done to find B:

plug your x value in the B equation:

5x + 25°

5(11) +25°

55 +25°

not sure if you can add here sorry :(. I hope this helped so far :)

5 0
3 years ago
I need answer fast plz
Elena L [17]

Answer:

use acacolator

Step-by-step explanation:

hhhhahahahahahahaahah pp

7 0
3 years ago
Can someone help on 18
Anuta_ua [19.1K]
A = 9 (Sorry I can't do the other ones, I haven't learned those ones yet) Hope this helps!! :P
7 0
3 years ago
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