X=cost per hamburgurs
y=cost per hot dog
200x+150y=1450
200x+250y=1750
we can multiply first equation by -1 and add to 2nd
-200x-150y=-1450
<u>200x+250y=1750 +</u>
0x+100y=300
100y=300
divide both sides by 100
y=3
sub back
200x+150y=1450
200x+150(3)=1450
200x+450=1450
minus 450 both sides
200x=1000
divide both sides by 200
x=5
the cost of a hamburgur is $5
the cost of a hot dog is $3
Hello!
To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.
This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.
In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.
Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.
y = 3x + b (substitute the ordered pair (4, 15))
15 = 3(4) + b (simplify)
15 = 12 + b (subtract 12 from both sides)
3 = b
Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.
Answer:
3rd choice
Step-by-step explanation:
the 3rd choice is the same as all of the others just in fraction form .you need to keep fraction form for the statement to still be true
(s + 3t) * (2s - 2t) = 2s^2 - 2st + 6ts - 6t^2
Hey there!
The main concept of pre-algebra is solving equations for variables in them.
For example, let's say you have the algebraic equation below.
x+1=3
With algebra, you need to figure what x is equal to. To do so, you will use inverse operations on both sides of the equation to isolate x one side, showing what it is equal to.
We would subtract 1 to both sides to isolate x on one side.
x+1-1=3-1
As you can see, +1-1=0, therefore, this would give us x+0, or just x. Now it is isolated and will show us what it is equal to.
x=3-1
x=2
Therefore, in our equation x+1=3, x would be equal to 2.
I hope this explanation helps! Have a great time here at Brainly!
