Answer: q = 40
Step-by-step explanation:
Given the quadratic formula as
x = [-b +/-√(b^2 -4ac)]/2a
b = -14
a = 1
c = q
Difference d between the two roots.
d = [-b + √(b^2 -4ac)]/2a - [-b -√(b^2 -4ac)]/2a
d = 2√(b^2 -4ac)/2a
d = √(b^2 -4ac)/a
And d = 6
Substituting the values of a,b and c. We have;
6 = √[(-14^2) - (4×1×q)]
Square both sides
6^2 = 196 - 4q
4q = 196 - 36
q = 160/4
q = 40
The equation becomes
x^2 - 14x + 40 = 0
Answer:
idont know answer
Step-by-step explanation:
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A
6x-14+18=10
6x+4=10
6x=6
X=1
Answer:
Step-by-step explanation:
Given that:
x + 4y = 30
x - 2y = 0
Subtracting both equations:
6y = 30
y = 30/6
y = 5
Putting in above equation
x + 4(5) = 30
x + 20 = 30
x = 10
i hope it will help you
Answer:
Step-by-step explanation:
Recall that ![\frac{x}{9}=\lfloor \frac{x}{9} \rfloor + 0.\overline{[x\:\mod9]}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B9%7D%3D%5Clfloor%20%5Cfrac%7Bx%7D%7B9%7D%20%5Crfloor%20%2B%200.%5Coverline%7B%5Bx%5C%3A%5Cmod9%5D%7D)
.
Therefore, 
.
