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3 years ago

The difference from home to

Mathematics

1 answer:

Amanda [17]3 years ago

6 0

Answer:

$\frac{3}{8}\ mile$

Step-by-step explanation:

-Amy walks a distance of 7/8 mile

-Tom walks a distance of 4/8 mile.

#We immediately notice that Amy has walked a longer distance than Tom.

We subtract Tom's distance from Amy's to find how much further Amy walked;

$\bigtriangleup d=d_A-d_T\\\\=\frac{7}{8}-\frac{4}{8}\\\\=\frac{3}{8} mile$

Hence, Amy has walked 3/8 miles further than Tom has.

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What is the equation of the horizontal line through (-7,-3)(−7,−3)?

Sholpan [36]

Answer:

y = -3

Step-by-step explanation:

This is because horizontal lines have a slope of 0. And for horizontal lines, the equation of the line is y = b. So, b is the y-intercept and the y intercept is -3 so that is the equation of the line.

3 0

3 years ago

Subtract (3 + 2i) from (-9-81)<br> 0 -17 – 51<br> 0-6 – 67<br> 0 -12 – 101<br> 0 12 + 101

harkovskaia [24]

Answer:

-12 - 10i.

Step-by-step explanation:

-9 - 8i - (3 + 2i)

= -9 - 8i - 3 - 2i

= -12 - 10i.

3 0

3 years ago

Inverse notation f^-1 used In a pure mathematics problem is not always used when finding inverses of applied problems. Rather, t

solong [7]

Answer:

a) 75.4 kg

b) $h(W)=\frac{W+83}{2.2}$

Step-by-step explanation:

a) The ideal weight of a 6-foot (72 inches) male is given by simply applying h= 72 in to the expression:

$W(72) = 49+2.2(72-60)\\W(72) =75.4\ kg$

b) Expressing height as a function of weight:

$W(h)= 49+2.2(h-60)\\2.2h-132+49=W\\h(W)=\frac{W+83}{2.2}$

Verifying with W(h(W)):

$W(h(W))= 49+2.2(\frac{W+83}{2.2} -60)\\W(h(W))= 49-132+W+83\\W(h(W))=W$

Verifying with h(W(h):

$h(W(h))=\frac{(49+2.2(h-60))+83}{2.2}\\h(W(h))=\frac{(49+2.2h-132+83)}{2.2}\\h(W(h))=h$

8 0

3 years ago

(4x-y=-15)<br>(3x-2y=-10)<br>

Andreyy89

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}4x-y=-15&\text{multiply both sides by (-2)}\\3x-2y=-10\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-8x+2y=30\\3x-2y=-10\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-5x=20\qquad\text{divide both sides by (-5)}\\.\qquad\qquad\boxed{x=-4}\\\\\\\text{Put the value of x to the first equation.}\\\\4(-4)-y=-15\\-16-y=-15\qquad\text{add 16 to both sides}\\-y=1\qquad\text{change the signs}\\\boxed{y=-1}$

5 0

3 years ago

Graph the linear equation x= - 5

Grace [21]

Answer:

that would be a vertical line (parallel to the y axis) that passes through -5 on the X axis

Step-by-step explanation:

just a straight line that goes through x = -5. if you're still confused it would also go through the point (-5, -5) a straight vertical line

5 0

3 years ago

Read 2 more answers